OpenTK鼠标选择

时间:2013-04-22 05:38:42

标签: c# opentk mouse-picking

我开发了一个小型C#示例,通过使用OpenTK和winforms

来选择点

有一种绘制方块的方法,还有另一种方法来选择三角形。不知怎的,我没有得到任何命中。 Readpixel方法有什么问题吗?因为我刚用正确的方法将Tao采样样本转换为OpenTK?你能告诉我我的方法有什么问题吗?

   private static int[,] board = new int[3, 3];        //Definition
   private const int BUFSIZE = 512;



   private void glControl1_MouseDown(object sender, MouseEventArgs e)
   {
        int[] selectBuffer = new int[BUFSIZE];              //This has to be redifined
        int hits;
        int[] viewport = new int[4];            

        if (e.Button == MouseButtons.Left)
        {
            GL.GetInteger(GetPName.Viewport, viewport);
            GL.SelectBuffer(BUFSIZE, selectBuffer);
            GL.RenderMode(RenderingMode.Select);
            GL.InitNames();
            GL.PushName(0);
            GL.MatrixMode(MatrixMode.Projection);
            GL.PushMatrix();
            GL.LoadIdentity();
            Byte4 Pixel = new Byte4();
            GL.ReadPixels(e.X, viewport[3] - e.Y, 1, 1, PixelFormat.Rgba, PixelType.UnsignedByte, ref Pixel);
            uint SelectedTriangle=SelectedTriangle = Pixel.ToUInt32();
            GL.Ortho(0, 3 ,0, 3, 1,-1); // Bottom-left corner pixel has coordinate (0, 0)                 
            DrawSquares(GL.RenderMode(RenderingMode.Select));
            GL.MatrixMode(MatrixMode.Projection);
            GL.PopMatrix();
            GL.Flush();
            hits = GL.RenderMode(RenderingMode.Render);
            ProcessHits(hits, selectBuffer);
            glControl1.SwapBuffers(); 
        }
    }



    private static void DrawSquares(int mode)
    {
        int i, j;
        for (i = 0; i < 3; i++)
        {
            if (mode == GL.RenderMode(RenderingMode.Select))                
                GL.LoadName(i);
            for (j = 0; j < 3; j++)
            {
                if (mode == GL.RenderMode(RenderingMode.Select))
                    GL.PushName(j);
                GL.Color3((float)i / 3.0f, (float)j / 3.0f, (float)board[i, j] / 3.0f);
                GL.Rect(i, j, (i + 1), (j + 1));
                if (mode == GL.RenderMode(RenderingMode.Select))
                    GL.PopName();
            }
        }
    }

1 个答案:

答案 0 :(得分:2)

我在代码中遇到了一些问题。它提出了这个问题。像这样更改实例。然后它会工作:)。一个小错误引起了一个大问题: - (

//(mode == GL.RenderMode(RenderingMode.Select))
(mode == RenderingMode.Select) // Removed GL.RenderMode