我正在创建一个使用xtable创建表并放入pdf文件的sweave文档。它工作,但表不适合文档,一些文本丢失。有没有办法在xtable中完全匹配xtable /将xtable完全匹配到pdf文件?
这是我的数据:
dput(x)
structure(list(App = structure(c(3L, 2L, 1L), .Label = c("AppServer",
"Db", "Web"), class = "factor"), Group = structure(c(2L, 1L,
1L), .Label = c("Back", "Front"), class = "factor"), Owner = structure(c(1L,
1L, 1L), .Label = "Infrasructure", class = "factor"), Server = structure(1:3, .Label = c("ServerA",
"ServerB", "ServerC"), class = "factor"), NumberCPU = c(64L,
120L, 120L), Description = structure(c(1L, 3L, 2L), .Label = c("Front End server to server web traffic",
"Hold Web templates to generate dynamic content", "Keeps customer data and login information"
), class = "factor"), Cost = structure(1:3, .Label = c("$200,000 ",
"$400,000 ", "$500,000 "), class = "factor")), .Names = c("App",
"Group", "Owner", "Server", "NumberCPU", "Description", "Cost"
), class = "data.frame", row.names = c(NA, -3L))
这是将表放在pdf中的代码:
print(xtable(x, caption=paste("Summary of applications"),table.placement="!h",caption.placement="top", align=c('l', 'p{1.5in}', rep('c',6) )))
答案 0 :(得分:4)
我建议查看xtable gallery,有很多有用的示例。基本上,如果您不想通过缩短字符串来调整表格,我会看到两个选项:
在这里,我结合使用两者:
\documentclass{article}
\usepackage{rotating}
\begin{document}
<<Data,echo=FALSE>>=
library(xtable)
x <- structure(list(App = structure(c(3L, 2L, 1L), .Label = c("AppServer",
"Db", "Web"), class = "factor"), Group = structure(c(2L, 1L,
1L), .Label = c("Back", "Front"), class = "factor"), Owner = structure(c(1L,
1L, 1L), .Label = "Infrasructure", class = "factor"), Server = structure(1:3, .Label = c("ServerA",
"ServerB", "ServerC"), class = "factor"), NumberCPU = c(64L,
120L, 120L), Description = structure(c(1L, 3L, 2L), .Label = c("Front End server to server web traffic",
"Hold Web templates to generate dynamic content", "Keeps customer data and login information"
), class = "factor"), Cost = structure(1:3, .Label = c("$200,000 ",
"$400,000 ", "$500,000 "), class = "factor")), .Names = c("App",
"Group", "Owner", "Server", "NumberCPU", "Description", "Cost"
), class = "data.frame", row.names = c(NA, -3L))
@
<<tab,echo=FALSE,results='asis'>>=
print(xtable(x, caption=paste("Summary of applications"),
caption.placement="top",
align=c('l', 'p{1.5in}', rep('c',6))),
size="footnotesize",
floating.environment="sidewaystable")
@
\end{document}
请注意,您必须使用LaTex包rotating
。这应该给你这样的东西:
答案 1 :(得分:1)
另一种解决方案是使用一些降价后端(knitr
,markdown
或pander
包)并使用{自动将表拆分为80个字符(或其他用户指定的宽度) {1}}。 E.g:
pander
结果可以轻松转换为pdf或LaTeX,然后直接从R > library(pander)
> res <- structure(list(App = structure(c(3L, 2L, 1L), .Label = c("AppServer", "Db", "Web"), class = "factor"), Group = structure(c(2L, 1L, 1L), .Label = c("Back", "Front"), class = "factor"), Owner = structure(c(1L, 1L, 1L), .Label = "Infrasructure", class = "factor"), Server = structure(1:3, .Label = c("ServerA", "ServerB", "ServerC"), class = "factor"), NumberCPU = c(64L, 120L, 120L), Description = structure(c(1L, 3L, 2L), .Label = c("Front End server to server web traffic", "Hold Web templates to generate dynamic content", "Keeps customer data and login information"), class = "factor"), Cost = structure(1:3, .Label = c("$200,000 ", "$400,000 ", "$500,000 "), class = "factor")), .Names = c("App", "Group", "Owner", "Server", "NumberCPU", "Description", "Cost"), class = "data.frame", row.names = c(NA, -3L))
> pander(res)
----------------------------------------------------
App Group Owner Server NumberCPU
--------- ------- ------------- -------- -----------
Web Front Infrasructure ServerA 64
Db Back Infrasructure ServerB 120
AppServer Back Infrasructure ServerC 120
----------------------------------------------------
Table: Table continues below
---------------------------------------
Description Cost
------------------------------ --------
Front End server to server web $200,000
traffic
Keeps customer data and login $400,000
information
Hold Web templates to generate $500,000
dynamic content
---------------------------------------
或pandoc
转换。