Question

假设我有一个表格，表明每个销售代表在特定月份销售的商品数量。但是，在没有销售的几个月内，某个人不会有争议。实施例

rep_id     month_yr     num_sales    
1          01/01/2012    3    
1          05/01/2012    1    
1          11/01/2012    1    
2          02/01/2012    2    
2          05/01/2012    1

我希望能够创建一个查询，显示每个rep_id和所有可能的月份（2012年1月1日，2012年1月2日，等等，通过当前）滚动12个月的销售额，如下所示：< / p>

rep_id     month_yr     R12_Sum    
1          11/01/2012   5    
1          12/01/2012   5    
1          01/01/2013   5    
1          02/01/2013   2

我在网上找到了一些例子，但我遇到的问题是我错过了每个rep_id的日期。我需要交叉加入吗？

Answer 1

要解决此问题，您需要一个包含所有年/月组合的驱动程序表。然后，您需要为每个代表创建它。

然后解决方案是将实际数据连接到此驱动程序并聚合所需的时间段。这是查询：

with months as (
    select 1 as mon union all select 2 union all select 3 union all select 4 union all
    select 5 as mon union all select 6 union all select 7 union all select 8 union all
    select 9 as mon union all select 10 union all select 11 union all select 12
   ),
    years as (select 2010 as yr union all select 2011 union all select 2012 union all select 2013
   ),
    monthyears as (
     select yr, mon, yr*12+mon as yrmon
     from months cross join years
    ),
     rmy as (
     select *
     from monthyears my cross join
          (select distinct rep_id from t
          ) r
    )
select rmy.rep_id, rmy.yr, rmy.mon, SUM(t.num_sales) as r12_sum
from rmy join
     t
     on rmy.rep_id = t.rep_id and
        t.year(month_yr)*12 + month(month_yr) between rmy.yrmon - 11 and rmy.yrmon
group by rmy.rep_id, rmy.yr, rmy.mon
order by 1, 2, 3

尚未经过测试，因此可能会出现语法错误。此外，它不会将年/月组合转换回日期，而是将值保留在不同的列中。

Answer 2

这是一个解决方案：

SELECT 
  a.rep_id
  ,a.month_yr
  ,SUM(b.R12_Sum) AS R12_TTM
FROM YourTable a
  LEFT OUTER JOIN YourTable b 
    ON a.rep_id = b.rep_id
    AND a.month_yr <= b.month_yr
    AND a.month_yr >= DATEADD(MONTH, -11, b.month_yr)
GROUP BY
  a.rep_id
  ,a.month_yr

Answer 3

当然不是很漂亮，但比CTE，数字表或自我加入更简单：

DECLARE @startdt DATETIME

SET @startdt = '2012-01-01'

SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= @startdt AND month_yr < DATEADD(MONTH,1,@startdt)

UNION ALL

SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= DATEADD(MONTH,1,@startdt) AND month_yr < DATEADD(MONTH,2,@startdt)

UNION ALL

SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= DATEADD(MONTH,2,@startdt) AND month_yr < DATEADD(MONTH,3,@startdt)

UNION ALL

SELECT rep_id, YEAR(month_yr), MONTH(month_yr), SUM(num_sales)
FROM MyTable WHERE month_yr >= DATEADD(MONTH,3,@startdt) AND month_yr < DATEADD(MONTH,4,@startdt)

UNION ALL

etc etc

Answer 4

以下演示使用CTE生成日期表并使用CTE生成摘要报告。如果没有适用的销售，销售代表将从结果中删除。

尝试摇晃报告参数，例如将@RollingMonths设置为1，以获得更多娱乐。

-- Sample data.
declare @Sales as Table ( rep_id Int, month_yr Date, num_sales Int );
insert into @Sales ( rep_id, month_yr, num_sales ) values
  ( 1, '01/01/2012', 3 ),
  ( 1, '05/01/2012', 1 ),
  ( 1, '11/01/2012', 1 ),
  ( 2, '02/01/2012', 1 ),
  ( 2, '05/01/2012', 2 );
select * from @Sales;

-- Reporting parameters.
declare @ReportEnd as Date = DateAdd( day, 1 - Day( GetDate() ), GetDate() ); -- The first of the current month.
declare @ReportMonths as Int = 6; -- Number of months to report.
declare @RollingMonths as Int = 12; -- Number of months in rolling sums.

-- Report.
--   A CTE generates a table of month/year combinations covering the desired reporting time period.
with ReportingIntervals as (
  select DateAdd( month, 1 - @ReportMonths, @ReportEnd ) as ReportingInterval,
    DateAdd( month, 1 - @RollingMonths, DateAdd( month, 1 - @ReportMonths, @ReportEnd ) ) as FirstRollingMonth
  union all
  select DateAdd( month, 1, ReportingInterval ), DateAdd( month, 1, FirstRollingMonth )
    from ReportingIntervals
    where ReportingInterval < @ReportEnd )
  -- Join the CTE with the sample data and summarize.
  select RI.ReportingInterval, S.rep_id, Sum( S.num_sales ) as R12_Sum
    from ReportingIntervals as RI left outer join
      @Sales as S on RI.FirstRollingMonth <= S.month_yr and S.month_yr <= RI.ReportingInterval
    group by RI.ReportingInterval, S.rep_id
    order by RI.ReportingInterval, S.rep_id

sql server滚动12个月与日期差距

4 个答案: