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Question

我有两张桌子：

deskcases：| CaseID | Resolved At(Date) | Labels |
ringcentral：| Date | Type | Action Result |

我的目标是在过去7天内获得以下输出：

| Date | Count of TotalResolvedCases | Count of Total Calls |

我需要在两个单独的表中计算案例和调用，然后按日期加入和分组计数。我也在处理两个表中不同的日期格式，因此古怪的group by和join函数。

我还需要让联接包含前7天的所有日期（deskcases包含所有日期，所以内部联接应该在这里工作吗？）

要关闭，我已经尝试在下面运行以下查询，它只是搅拌一两分钟后没有结果。关于如何使这个工作的任何想法？预先感谢您的帮助！： - ）

（运行MySQL 5.0.96）

SELECT
DATE_FORMAT(
    deskcases.`Resolved At`,
    '%Y-%m-%d'
)AS Date1,
(
    SELECT
        COUNT(deskcases.`Case #`)
    FROM
        deskcases
    WHERE
        deskcases.Labels NOT LIKE '%SPAM%'
    AND deskcases.Labels NOT LIKE '%Online Orders%'
    AND deskcases.Labels NOT LIKE '%Internal SPAM%'
    AND deskcases.`Resolved At` > NOW()- INTERVAL 8 DAY
)AS TotalResolvedCases,
(
    SELECT
        COUNT(ringcentral.Counter)
    FROM
        ringcentral
    WHERE
        `ringcentral`.`Type` = 'Voice'
    AND `Action Result` = 'Accepted'
    AND ringcentral.`Date` > NOW()- INTERVAL 8 DAY
)AS TotalCalls
FROM
 deskcases
INNER JOIN ringcentral ON DATE_FORMAT(
 deskcases.`Resolved At`,
 '%Y-%m-%d'
)= ringcentral.Date
GROUP BY
 Date1
ORDER BY
 Date1 ASC

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我能够略微编辑这个给我一些结果，但似乎我在计算所有案例并使用我的子选择查询进行调用，并且总计不按日期分组。这是代码：

SELECT
DATE_FORMAT(
    deskcases.`Resolved At`,
    '%Y-%m-%d'
)AS Date1,
(
    SELECT
        COUNT(deskcases.`Case #`)
    FROM
        deskcases
    WHERE
        deskcases.Labels NOT LIKE '%SPAM%'
    AND deskcases.Labels NOT LIKE '%Online Orders%'
    AND deskcases.`Case Status` LIKE '%Resolved%'
)AS TotalResolvedCases,
(
    SELECT
        COUNT(ringcentral.Counter)
    FROM
        ringcentral
    WHERE
        `ringcentral`.`Type` = 'Voice'
    AND `Action Result` = 'Accepted'
)AS TotalCalls
FROM
  deskcases
LEFT OUTER JOIN ringcentral ON DATE_FORMAT(
  deskcases.`Resolved At`,
  '%Y-%m-%d'
)= ringcentral.Date
WHERE deskcases.`Resolved At` > NOW()- INTERVAL 8 DAY
GROUP BY
  Date1
ORDER BY
  Date1 ASC

Answer 1

在这种情况下，你绝对不应该加入约会。

例如，您可能拥有以下数据：

deskcases                           ringcentral
---------                           -----------
date      | whatever_d              date      | whatever_r
----------------------              ----------------------
today       x                       yesterday   u
yesterday   y
yesterday   z

现在，当你加入他们时，你会得到这个：

joinedTable
-----------
date      | whatever_d  |  whatever_r
-------------------------------------
today       x 
yesterday   y              u
yesterday   z              u

哎呀，你从铃声表中得到了2次，但你只想要1.

那么，你如何得到你的数据？写下2个语句或将它们与UNION组合：

SELECT
DATE(`Resolved At`) AS Date1,
"Deskcases" AS fromTable,
COUNT(*) AS TotalNumber
FROM
        deskcases
    WHERE
        deskcases.Labels NOT LIKE '%SPAM%'
    AND deskcases.Labels NOT LIKE '%Online Orders%'
    AND deskcases.Labels NOT LIKE '%Internal SPAM%'
    AND deskcases.`Resolved At` > CURDATE()- INTERVAL 8 DAY
GROUP BY 1, 2
UNION ALL
SELECT
`Date` AS Date1,
"ringcentral" AS fromTable,
COUNT(*) AS TotalNumber
FROM
        ringcentral
    WHERE
        `ringcentral`.`Type` = 'Voice'
    AND `Action Result` = 'Accepted'
    AND ringcentral.`Date` > CURDATE()- INTERVAL 8 DAY
GROUP BY 1, 2

另请注意，我已将NOW()更改为CURDATE()。在deskcases表中，您的日期列似乎是一个时间戳。当您从'2013-03-20 10:06:00'减去8天后，您将获得'2013-03-12 10:06:00'，因此您将丢失'2013-03-12之间的所有行00:00:00'和'2013-03-12 10:05:59'。我还使用了DATE()函数而不是DATE_FORMAT()。 DATE_FORMAT()在许多方面都是非常好用且有用的功能，但在这种情况下，使用DATE()时必须输入较少的字符：）

<强>更新

SELECT 
Date1, 
SUM(CASE WHEN fromTable = 'Deskcases' THEN TotalNumber ELSE 0 END) AS TotalDeskcases,
SUM(CASE WHEN fromTable = 'ringcentral' THEN TotalNumber ELSE 0 END) AS TotalRingcentral 
FROM (
SELECT
DATE(`Resolved At`) AS Date1,
'Deskcases' AS fromTable,
COUNT(*) AS TotalNumber
FROM
        deskcases
    WHERE
        deskcases.Labels NOT LIKE '%SPAM%'
    AND deskcases.Labels NOT LIKE '%Online Orders%'
    AND deskcases.Labels NOT LIKE '%Internal SPAM%'
    AND deskcases.`Resolved At` > CURDATE()- INTERVAL 8 DAY
GROUP BY 1, 2
UNION ALL
SELECT
`Date` AS Date1,
'ringcentral' AS fromTable,
COUNT(*) AS TotalNumber
FROM
        ringcentral
    WHERE
        `ringcentral`.`Type` = 'Voice'
    AND `Action Result` = 'Accepted'
    AND ringcentral.`Date` > CURDATE()- INTERVAL 8 DAY
GROUP BY 1, 2
) sq
GROUP BY Date1

MySQL计数IF和JOIN

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1 个答案: