我正在尝试实现一些涉及在托管C#和非托管C ++代码之间编组数组的项目。我遇到了一个问题,我在网上找到的解决方案似乎都没有。我非常感谢有关这方面的任何意见。
我没有提供完整的代码,但是非常简化的部分显示了这个问题。虽然它看起来像一个大块 - 它很简单 - 只是概念性的。只想尽可能多地给出全貌。
C ++部分:
Object.h
class cObject
{
public:
//...constructor, destructor...
int Method_Known_Size(double* array, int size);
int Method_Unknown_Size(double* array);
...
void FreeArray(double* p);
}
Object.cpp
int Method_Known_Size(double* array, int size)
{
//modify array somehow..
for(int i=0; i<size; i++) array[i] = i;
}
int method_Unknown_Size(double* array)
{
int size = 9;
array = new double[size];
for(int i=0; i<size; i++) array[i] = i;
}
(跳过Caller.h) Caller.cpp
//...callers for constructor, destructor, for releasing unmanaged memory...
extern "C" int __stdcall Run_Known_Size(cObject* pObject, double* array, int size)
{
return cObject->Method_Known_Size(array, size);
}
extern "C" int __stdcall Run_Unknown_Size(cObject* pObject, double* array)
{
return cObject->Method_Unknown_Size(array);
}
extern "C" void __stdcall Release(cObject* cObject, double* array)
{
if(cObject != NULL) cObject->FreeArray(array);
}
因此,基本上Run_Known_Size
方法只修改已经由C#内存分配的内容,Run_Unknown_Size
创建数组并修改它。
C#部分
public class DllWrapper: IDisposable
{
/* Creating an object, disposing,...
[DllImport("cObject.dll")]
CreateObject();...DisposeObject(IntPtr pObject);
...CallFreeArray(IntPtr pArray);*/
[DllImport("cObject.dll")]
private static extern int CallRun_Known_Size(IntPtr pObject,
[Out] double [] arr_allocated, int size);
[DllImport("cObject.dll")]
private static extern int CallRun_Unknown_Size(IntPtr pObject,
[Out] IntPtr arr_not_allocated);
private IntPtr m_pNativeObject;
public DllWrapper()
{
this.m_pNativeObject = CreateObject();
}
public void Dispose()
{
Dispose(true);
}
protected virtual void Dispose(bool bDisposing)
{
if (this.m_pNativeObject != IntPtr.Zero)
{
DisposeObject(this.m_pNativeObject);
this.m_pNativeObject = IntPtr.Zero;
}
if (bDisposing)
{
GC.SuppressFinalize(this);
}
}
~DllWrapper()
{
Dispose(false);
}
public void ReleaseUnmanAraray(IntPtr pArr)
{
CallFreeArray(pArr);
}
public int Run_Known_Size(double[] arr_allocated, int size)
{
return CallRun_Known_Size(this.m_pNativeObject, arr_allocated, size);
}
public int Run_Unknown_Size(IntPtr arr_not_allocated)
{
return CallRun_Known_Size(this.m_pNativeObject, arr_not_allocated);
}
}
static void Main(string[] args)
{
double[] alloc_arr = new double[] { 1, 5, 3, 3, 5, 5, 8, 9,1 };
int size = 9;
double[] Arr_for_Copy = new double[size];
IntPtr pArr = new IntPtr();
DllWrapper wrapper = new DllWrapper();
int res1 = Run_Known_Size(alloc_arr, size);
int res2 = Run_Unknown_size(pArr);
if (pArr != IntPtr.Zero) // pArr IS ZERO ALWAYS!!!!!!
{
Marshal.Copy(pArr, Arr_for_Copy, 0, size);
}
else
{
Console.WriteLine("Pointer was zero again");
}
wrapper.ReleaseUnmanAraray(pScores);
wrapper.Dispose();
Console.ReadLine();
}
使用C#分配的数组一切正常 - 它们是从C ++中修改而没有错误的。但是,如果我不知道数组的大小,因此无法预分配数组,我找到的唯一解决方案是传递[Out] IntPtr并让C ++管理内存,分配和修改数组。然后返回的IntPtr可以编组到C#的double []数组,因为我们已经知道了大小(为了简化我只是将数字4作为大小,但我传递int * size来确定大小)。
在传递IntPtr并基于此指针在C ++中创建数组后,我的所有测试都以零指针(没有错误)结束。
我见过涉及COM对象的解决方案,但由于可移植性问题,我不得不避免使用它。
提前致谢。
答案 0 :(得分:5)
Method_Unknown_Size
的参数为double*
,您正在更改参数本身。如果要更改调用者发送的原始值,则应将参数定义为指向数组的指针,这意味着指向double 或引用的指针指向双
你还应该以某种方式告诉调用者数组的大小(我猜你已经管理过了)。
C ++:
int method_Unknown_Size(double *&array)
{
int size = 9;
array = new double[size];
for(int i=0; i<size; i++) array[i] = i;
return size;
}
void FreeArray(double *&p)
{
delete[] p;
p = NULL;
}
extern "C" int __stdcall Run_Unknown_Size(cObject *pObject, double *&array)
{
return cObject->Method_Unknown_Size(array);
}
extern "C" void __stdcall Release(cObject *cObject, double *&array)
{
if(cObject != NULL) cObject->FreeArray(array);
}
C#:
[DllImport("cObject.dll")]
private static extern int Run_Unknown_Size(IntPtr pObject,
out IntPtr arr_not_allocated);
[DllImport("cObject.dll")]
private static extern int Release(IntPtr pObject,
ref IntPtr arr_not_allocated);
// to allocate the array:
IntPtr pArr;
int res2 = Run_Unknown_size(m_pNativeObject, out pArr);
// to free the array:
Release(m_pNativeObject, ref pArr);
这绝对有效!告诉我,如果没有!