这是构造函数:
public PartyRoleRelationship(PartyRole firstRole, PartyRole secondRole)
{
if (firstRole == secondRole)
throw new Exception("PartyRoleRelationship cannot relate a single role to itself.");
if (firstRole.OccupiedBy == null || secondRole.OccupiedBy == null)
throw new Exception("One or both of the PartyRole parameters is not occupied by a party.");
// Connect this relationship with the two roles.
_FirstRole = firstRole;
_SecondRole = secondRole;
T = _FirstRole.GetType().MakeGenericType();
_SecondRole.ProvisionRelationship<T>(_FirstRole); // Connect second role to this relationship.
}
在最后一行,它在_SecondRole上调用ProvisionRelationship,它给了我运行时错误:无法找到类型或名称空间“T”...
我如何(a)正确分配T,或(b)使用构造函数传递泛型?我一直在查看相当多的帖子,但可能由于缺乏理解而遗漏了一些内容。任何人对此的帮助将不胜感激。
答案 0 :(得分:12)
你的课程必须是通用的。所以PartyRoleRelationship
需要看起来像这样:
public class PartyRoleRelationship<T>
{
public PartyRoleRelationship(T arg, ...)
{
}
}
在此处阅读有关泛型类的更多信息:
http://msdn.microsoft.com/en-us/library/sz6zd40f(v=vs.80).aspx
http://msdn.microsoft.com/en-us/library/ms379564(v=vs.80).aspx
编辑:
你可能会简化你的代码并按照这样做:
public class RoleRelationship<T>
{
public RoleRelationship(T firstRole, T secondRole)
{
if (firstRole.OccupiedBy == null || secondRole.OccupiedBy == null)
throw new Exception("One or both of the Role parameters is not occupied by a party.");
// Connect this relationship with the two roles.
_FirstRole = firstRole;
_SecondRole = secondRole;
_SecondRole.ProvisionRelationship<T>(_FirstRole);
}
}
答案 1 :(得分:4)
创建泛型类,其中泛型类型T是基类PartyRole的类型:
public class PartyRoleRelationship<T> where T : PartyRole
{
T _FirstRole;
T _SecondRole;
public PartyRoleRelationship(T role1, T role2) {
_FirstRole = role1;
_SecondRole = role2;
role1.ProvisionRelationship(role2)
}
public ProvisionRelationship(T otherRole) {
// Do whatever you want here
}
}
答案 2 :(得分:0)
如果您静态知道_FirstRole的类型(是PartyRole吗?),您可以使用它:
_SecondRole.ProvisionRelationship<PartyRole>(_FirstRole);