我创建了以下嵌套表单数组;
return array(
'elements' => array(
'contact' => array(
'type' => 'form',
'elements' => array(
'first_name' => array(
'type' => 'text',
),
'last_name' => array(
'type' => 'text',
)
),
),
'lead' => array(
'type' => 'form',
'elements' => array(
'primary_skills' => array(
'type' => 'textarea',
),
),
),
),
'buttons' => array(
'save-lead' => array(
'type' => 'submit',
'label' => 'Create',
'class' => 'btn'
),
)
);
我有这样的视图页面
echo $form->renderBegin();
echo $form['lead'];
echo $form['contact'];
echo $form->buttons['save-lead'];
echo $form->renderEnd();
我的actionCreate就像这样
$form = new CForm('application.views.leads.register');
$form['lead']->model = new Lead;
$form['contact']->model = new Contact;
// how can i perform ajax validation only for $form['contact']
$this->performAjaxValidation($model);
//if contact form save btn is clicked
if ($form->submitted('save-lead') && $form['contact']->validate() &&
$form['lead']->validate()
) {
$contact = $form['contact']->model;
$lead = $form['lead']->model;
if ($contact->save()) {
$lead->contact_id = $contact->id;
if ($lead->save()) {
$this->redirect(array('leads/view', 'id' => $lead->id));
}
}
}
ajax验证方法是
protected function performAjaxValidation($model)
{
if (isset($_POST['ajax']) && $_POST['ajax'] === 'contact') {
echo CActiveForm::validate($model);
Yii::app()->end();
}
}
所以我的问题是如何在$ form ['contact']和$ form ['lead']元素上单独执行ajax验证?
答案 0 :(得分:1)
您可以在页面中包含多个表单,但不应嵌套它们。 嵌套表单无效。
答案 1 :(得分:0)
您应该进行自己的验证
在你必须添加的控制器的actionCreate和actionUpdate中(我有主模型“Invoice”和辅助“InvoiceDetails”,并且InvoiceDetails可以有多个表单)。但当然形式不能嵌套!
public function actionCreate()
{
...
$PostVar = 'Invoices';
if (Yii::app()->request->isAjaxRequest)
{ // if ajax
$this->performAjaxValidation($model, strtolower($PostVar) . '-form');
$PostVar = ucfirst($PostVar);
if (isset($_POST[$PostVar]))
{
$model->attributes = $_POST[$PostVar];
$dynamicModel = new InvoiceDetails(); //your model
$valid = self::validate($model, $dynamicModel);
if (!isset($_POST['ajax']))
{
if (isset($_POST['InvoiceDetails']))
{
$allDetails = array();
$allDynamicModels = $_POST['InvoiceDetails'];
//your own customization
foreach ($allDynamicModels as $key => $value)
{
$InvDet = InvoiceDetails::model()->findByPk($_POST['InvoiceDetails'][$key]['id']);
if (!isset($InvDet))
{
$InvDet = new InvoiceDetails();
}
$InvDet->attributes = $_POST['InvoiceDetails'][$key];
$InvDet->save();
$allDetails[] = $InvDet;
}
}
$model->invoicedetails = $allDetails;
if ($model->save())
{
echo CJSON::encode(array('status' => 'success'));
Yii::app()->end();
}
else
{
echo CJSON::encode(array('status' => 'error saving'));
Yii::app()->end();
}
}
// Here we say if valid
if (!isset($valid))
{
echo CJSON::encode(array('status' => 'success'));
}
else
{
echo $valid;
}
Yii::app()->end();
}
else
{
$this->renderPartial('_form', ...);
}
}
else
{
// not AJAX request
$this->render('_form', ...));
}
答案 2 :(得分:0)
嵌套表单无效。您可以使用scenarios在不同的实例中验证表单。
示例:
`if ($form->submitted('save-lead'){
$form->scenario = 'save-lead';
if($form->validate()) {
$form->save();
}
} else {
$form->scenario = 'contact';
if($form->validate()){
$form->save();
}
}
$this->render('_form', array('form'=>$form);`