Question

我收到了这个错误。

我的 web.xml 有此

<servlet>
  <servlet-name>springweb</servlet-name>
  <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
   <init-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/web-application-config.xml</param-value>
   </init-param>
  <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
  <servlet-name>springweb</servlet-name>
  <url-pattern>/app/*</url-pattern>
</servlet-mapping>

我在web-application-config.xml

中有这个

<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
       <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/>
</bean>

<bean name="/Scheduling.htm" class="com.web.SchedulingController"/>

我的com.web.SchedulingController看起来像这样

/*
* To change this template, choose Tools | Templates
* and open the template in the editor.
*/

package com.web; 

import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.springframework.web.servlet.ModelAndView;
import org.springframework.web.servlet.mvc.Controller;


public class SchedulingController implements Controller{

public ModelAndView handleRequest(HttpServletRequest request, HttpServletResponse response) throws Exception {

    ModelAndView modelAndView = new ModelAndView("/jsp/Scheduling_main.jsp");
    modelAndView.addObject("message","Hello World MVC!!");
    return modelAndView;
}
}

当我使用网址http://localhost:8080/project1/app/Scheduling.htm点击此控制器时 Scheduling_main.jsp显示但图像显示不正确。 js和css文件也没有被渲染。

我正在访问这样的图片

<img src="jquerylib/images/save_32x32.png" title="Save Appointment">

如果我将servlet定义中的URL映射更改为* .htm，则图像显示正常。你能指出我错过的地方吗？

这是完整的错误消息

WARN  [PageNotFound] No mapping found for HTTP request with URI [/mavenproject1/app/jquerylib/images/save_32x32.png] in DispatcherServlet with name 'springweb'

非常感谢。拉维

Answer 1

我认为这是因为您尝试通过servlet获取图像（映射为/ app / *）您需要获取静态内容而不使用servlet处理它，例如将图像源设置为

<img src="../jquerylib/images/save_32x32.png" title="Save Appointment">

然后您的图像的真实URI将是/mavenproject1/jquerylib/images/save_32x32.png，它将由您的tomcat按原样返回，无需任何处理。

Answer 2

我只需在spring默认规则（/ **）之前添加三条规则到tuckey的urlrewritefilter（urlrewrite.xml）来解决问题

<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE urlrewrite PUBLIC "-//tuckey.org//DTD UrlRewrite 3.0//EN" "http://tuckey.org/res/dtds/urlrewrite3.0.dtd">
    <urlrewrite default-match-type="wildcard">
        <rule>
            <from>/</from>
            <to>/app/welcome</to>
        </rule>
        <rule>
            <from>/scripts/**</from>
            <to>/scripts/$1</to>
        </rule>
        <rule>
            <from>/styles/**</from>
            <to>/styles/$1</to>
        </rule>
        <rule>
            <from>/images/**</from>
            <to>/images/$1</to>
        </rule>
        <rule>
            <from>/**</from>
            <to>/app/$1</to>
        </rule>
        <outbound-rule>
            <from>/app/**</from>
            <to>/$1</to>
        </outbound-rule>    
    </urlrewrite>

How to handle static content in Spring MVC?

Answer 3

您可以查看此网址，希望对您有所帮助

http://www.javabloger.com/article/no-mapping-found-for-http-request-with-uri.html

没有找到带有URI的HTTP请求的映射：在Spring MVC应用程序中

3 个答案: