Question

假设我在名为“main”的列表中有一堆字符串。如何遍历“main”，如果找到匹配项，则删除“main”中匹配的部分，然后将匹配的文本添加到名为“new”的新列表中？

蟒

main = ['text \fc + \fr this is my match1 \fc* text', 'text \fc + \fr this is my match2 \fc* text', 'text', 'text', 'text \fc + \fr this is my match \fc* text']
new = []

def rematch(pattern, inp):
  matcher = re.compile(pattern)
  matches = matcher.match(inp)
  if matches:
    new.append(matches)
    #remove match from "main" somehow?

for x in main:
  for m in rematch('\\fc \+ \\fr(.*?)\\fc\*', x):

结果：

main = ['text text', 'text text', 'text', 'text', 'text text']

new = ['this is my match1', 'this is my match2', 'this is my match3']

Answer 1

In [33]: import re

In [34]: pat = re.compile('\\fc \+ \\fr(.*?)\\fc\*')

In [43]: main, new = zip(*[(''.join(parts[::2]), ''.join(parts[1::2])) for parts in [pat.split(m) for m in main]])

In [44]: new = [n.strip() for n in new if n]

In [45]: main
Out[45]: ('text  text', 'text  text', 'text', 'text', 'text  text')

In [46]: new
Out[46]: ['this is my match1', 'this is my match2', 'this is my match']

说明：

请注意使用pat.split时会发生什么：

In [37]: pat.split(main[0])
Out[37]: ['text ', ' this is my match1 ', ' text']

除了您想要main中的奇数术语和new中的偶数术语之外，这与您想要的类似。我们将在一秒钟内完成。

首先，我们将pat.split应用于main中的每个项目：

In [51]: [pat.split(m) for m in main]
Out[51]: 
[['text ', ' this is my match1 ', ' text'],
 ['text ', ' this is my match2 ', ' text'],
 ['text'],
 ['text'],
 ['text ', ' this is my match ', ' text']]

接下来，让我们将奇数项与偶数项分开，并使用''.join将项目一起刷成一个字符串：

In [52]: [(''.join(parts[::2]), ''.join(parts[1::2])) for parts in [pat.split(m) for m in main]]
Out[52]: 
[('text  text', ' this is my match1 '),
 ('text  text', ' this is my match2 '),
 ('text', ''),
 ('text', ''),
 ('text  text', ' this is my match ')]

从这里开始，我们可以使用zip(*...)将main与new分开：

In [53]: main, new = zip(*[(''.join(parts[::2]), ''.join(parts[1::2])) for parts in [pat.split(m) for m in main]])

In [54]: main
Out[54]: ('text  text', 'text  text', 'text', 'text', 'text  text')

In [55]: new
Out[55]: (' this is my match1 ', ' this is my match2 ', '', '', ' this is my match ')

将匹配添加到新列表并从原始列表中删除匹配

1 个答案: