Question

我有这个查询，它连接存储在缓存表中的事件名称。

SELECT OccurrenceCache.occurrence_date, CalendarItem.summary FROM OccurrenceCache
    INNER JOIN CalendarItem ON CalendarItem.ROWID = OccurrenceCache.event_id
    WHERE OccurrenceCache.occurrence_date >= (strftime('%s', 'now', 'localtime', 'start of day') - strftime('%s', '2001-01-01', 'start of day')) AND OccurrenceCache.occurrence_end_date <= (strftime('%s', 'now', 'localtime', 'start of day') - strftime('%s', '2001-01-01', 'start of day') + 24 * 60 * 60);

现在我想要包含事件的位置数据，这些数据存储在名为 Location 的表中。 CalendarItem.location_id引用位置条目（0表示未指定位置）。我用另一个JOIN语句尝试了它，但它不起作用：

SELECT OccurrenceCache.occurrence_date, CalendarItem.summary, Location.title FROM OccurrenceCache
    INNER JOIN CalendarItem ON CalendarItem.ROWID = OccurrenceCache.event_id
    INNER JOIN Location ON Location.ROWID = CalendarItem.location_id
    WHERE OccurrenceCache.occurrence_date >= (strftime('%s', 'now', 'localtime', 'start of day') - strftime('%s', '2001-01-01', 'start of day')) AND OccurrenceCache.occurrence_end_date <= (strftime('%s', 'now', 'localtime', 'start of day') - strftime('%s', '2001-01-01', 'start of day') + 24 * 60 * 60);

返回0结果。

Answer 1

如果Location表中的所有条目与calenderitem表不匹配，则使用LEFT JOIN代替解决方案。

SELECT OccurrenceCache.occurrence_date, CalendarItem.summary, Location.title FROM OccurrenceCache
    INNER JOIN CalendarItem ON CalendarItem.ROWID = OccurrenceCache.event_id
    LEFT JOIN Location ON Location.ROWID = CalendarItem.location_id
    WHERE OccurrenceCache.occurrence_date >= (strftime('%s', 'now', 'localtime', 'start of day') - strftime('%s', '2001-01-01', 'start of day')) AND OccurrenceCache.occurrence_end_date <= (strftime('%s', 'now', 'localtime', 'start of day') - strftime('%s', '2001-01-01', 'start of day') + 24 * 60 * 60);

Using Outer Joins in SQL

如何在SQL中实现这种双连接？

1 个答案: