Question

此查询正常

SELECT 1 AS TAG, NULL AS parent, 1 [dog!1]
UNION (SELECT 1,NULL, 3) 
FOR XML EXPLICIT, ROOT('dogs')

我想将它分配给变量。没有联合，这可以正常工作：

DECLARE @x xml
SET @x = ((
  (SELECT 1 AS TAG, NULL AS parent, 1 [dog!1]
   FOR XML EXPLICIT, ROOT('dogs'))
  ))

一旦我介绍了工会，它就不起作用了：

DECLARE @x xml
SET @x = ((
  (SELECT 1 AS TAG, NULL AS parent, 1 [dog!1]
   UNION (SELECT 1,NULL, 3) 
   FOR XML EXPLICIT, ROOT('dogs'))
   ))

尝试过各种各样的事情。我缺少什么

Answer 1

您只需要再添加一个子查询级别：

DECLARE @X XML = 
(
  SELECT * FROM
  (
    SELECT 1 AS TAG, NULL AS parent, 1 [dog!1]
    UNION 
    SELECT 1,NULL, 3
  )X
  FOR XML EXPLICIT, ROOT('dogs')
);

SELECT @X;

将FOR XML EXPLICIT UNION的结果分配给变量

1 个答案: