Question

如果相隔3分钟，如何从数组中获取值？这是我的数组，$ array1

 Array ( 
[0] => Array ( [id] => 47523 [date] => 12-02-13 14:36:32 ) 
[1] => Array ( [id] => 65454 [date] => 12-02-13 14:36:32 ) 
[2] => Array ( [id] => 47523 [date] => 12-02-13 13:56:48 ) 
[3] => Array ( [id] => 38639 [date] => 12-02-13 13:56:48 ) 
[4] => Array ( [id] => 38639 [date] => 12-02-13 13:08:51 ) 
[5] => Array ( [id] => 38639 [date] => 12-02-13 13:07:43 ) 
[6] => Array ( [id] => 38639 [date] => 12-02-13 13:09:43 ) 
)

我如何获得此输出

Array ( 
[0] => Array ( [id] => 38639 [date] => 12-02-13 13:08:51 ) 
[1] => Array ( [id] => 38639 [date] => 12-02-13 13:07:43 ) 
[2] => Array ( [id] => 38639 [date] => 12-02-13 13:09:43 ) 
)

Answer 1

使用strtotime获取时间戳，然后比较时间戳。

Answer 2

将日期存储为时间（）;

...然后

function filterArray3minutes($array) {
  foreach($array as $item) {
   foreach($array as $item2) {
     if($item[date] > $item2[date]-3*60 && $item[date] < $item2[date]+3*60 && !isset($array2[$item[id]]) $array2[$item[id]] = $item;
     }
  }
  foreach($array2 as $item) {
     $array3[] = $item;
  }
   return $array3;
}

我认为将时间保持为整数只是输入和输出的异常是非常好的做法，它可以更快地使用它。

编辑：现在这个功能可以让物品相隔3分钟，避免重复输入......我想你不能想要更多。

Answer 3

不确定你是如何得到你的结果但看起来不对.....因为它们可能是4种不同的结果。

想象一下

$data = array(
  0 => Array ( 'id' => 47523, 'date' => "12-02-13 14:36:32" ),
  1 => Array ( 'id' => 47523, 'date' => "12-02-13 13:56:48" ),
  2 => Array ( 'id' => 65454, 'date' => "12-02-13 14:36:32" ),
  3 => Array ( 'id' => 38639, 'date' => "12-02-13 13:56:48" ),
  4 => Array ( 'id' => 38639, 'date' => "12-02-13 13:08:51" ),
  5 => Array ( 'id' => 38639, 'date' => "12-02-13 13:07:43" ),
  6 => Array ( 'id' => 38639, 'date' => "12-02-13 13:09:43" ),
);

示例

var_dump(getDiff($data)); var_dump(getDiff($data,SORT_ASC)); var_dump(getDiff($data,SORT_DESC));

<强> SORT_NONE

array (size=3) 0 => array (size=2) 'id' => int 47523 'date' => string '12-02-13 13:56:48' (length=17) 1 => array (size=2) 'id' => int 38639 'date' => string '12-02-13 13:08:51' (length=17) 2 => array (size=2) 'id' => int 38639 'date' => string '12-02-13 13:07:43' (length=17)

输出XSORT_ASC

array (size=4) 0 => array (size=2) 'id' => int 38639 'date' => string '12-02-13 13:08:51' (length=17) 1 => array (size=2) 'id' => int 38639 'date' => string '12-02-13 13:09:43' (length=17) 2 => array (size=2) 'id' => int 47523 'date' => string '12-02-13 13:56:48' (length=17) 3 => array (size=2) 'id' => int 47523 'date' => string '12-02-13 14:36:32' (length=17)

输出XSORT_DESC

array (size=4) 0 => array (size=2) 'id' => int 65454 'date' => string '12-02-13 14:36:32' (length=17) 1 => array (size=2) 'id' => int 47523 'date' => string '12-02-13 13:56:48' (length=17) 2 => array (size=2) 'id' => int 38639 'date' => string '12-02-13 13:08:51' (length=17) 3 => array (size=2) 'id' => int 38639 'date' => string '12-02-13 13:07:43' (length=17)

使用的功能

function getDiff(array $data, $sort = 0) { switch ($sort) { case SORT_ASC : usort($data, function ($a, $b) { $a = strtotime($a['date']); $b = strtotime($b['date']); return ($a == $b) ? 0 : (($a < $b) ? -1 : 1); }); break; case SORT_DESC : usort($data, function ($a, $b) { $a = strtotime($a['date']); $b = strtotime($b['date']); return ($a == $b) ? 0 : (($a < $b) ? 1 : -1); }); break; } $it = new CachingIterator(new ArrayIterator($data), CachingIterator::FULL_CACHE); $list = array(); foreach ( $it as $var ) { if ($it->hasNext()) { $date = strtotime($var['date']); $date2 = $it->getInnerIterator()->current(); $date2 = strtotime($date2['date']); $diff = ($sort === SORT_DESC || $sort === 0) ? $date - $date2 : $date2 - $date ; if ($diff <= (60 * 3)) { $list[] = $it->getInnerIterator()->current(); } } } return $list; }

结论

这取决于元素中日期的位置....

PHP：如何从数组中获取每个元素3分钟的值？

3 个答案: