PHP上传重命名图像并作为附件发送到电子邮件中

时间:2013-02-04 13:09:31

标签: php

我忙于PHP上传和邮件功能基本上它需要上传的图像并将其作为附件放入电子邮件中,然后还将其上传到目录,我将如何根据日期重命名图像但保留扩展,对于人们可以上传具有相同文件名的图像...

这是上传功能:

$newdirectory = "applicants";
$count = 0;
foreach ($_FILES['myfile']['name'] as $filename)
{
    $temp = $_FILES['myfile']['tmp_name'][$count];
    move_uploaded_file($temp, $newdirectory . '/' . $filename);
    $count++;
}

然后整个php函数:

<?php
    function printMember($member) {
        foreach($member as $key=>$value) {
            //Fill the aux string first
            $str.= "$key : $value <br />";
        }
        //string that will be added to $msg variable inside the loop
        return $str;
    }

    $json = $_POST['parameters'];
    $json_string = stripslashes($json);
    $data = json_decode($json_string, true);
    $depCount = count($data["dependants"]);

    $msg .= "<h2>Main member data:</h2>";
    $msg .= printMember($data["mainmember"]);
    $msg .= "<h2>There are $depCount Dependants</h2>";

    foreach ($data["dependants"] as $index => $dependant) {
       $msg .= "<h2>Dependant $index</h2>";
       $msg .= printMember($dependant);
    }

    $strTo = "chante@jamfactory.co.za";
    $strSubject = "Image Testing";
    $strMessage = nl2br($msg);

    //*** Uniqid Session ***//
    $strSid = md5(uniqid(time()));

    $strHeader = "";
    $strHeader .= "From: Dawid<xxx@xxx.co.za>\nReply-To:xxxx@xxx.co.za";

    $strHeader .= "MIME-Version: 1.0\n";
    $strHeader .= "Content-Type: multipart/mixed; boundary=\"".$strSid."\"\n\n";
    $strHeader .= "This is a multi-part message in MIME format.\n";

    $strHeader .= "--".$strSid."\n";
    $strHeader .= "Content-type: text/html; charset=utf-8\n";
    $strHeader .= "Content-Transfer-Encoding: 7bit\n\n";
    $strHeader .= $strMessage."\n\n";

    //*** Attachment ***//
    $count = 0;
    foreach($_FILES['myfile']['name'] as $filename)
    {
        $temp = $_FILES['myfile']['tmp_name'][$count];
        $strFilesName = $filename;
        $strContent = chunk_split(base64_encode(file_get_contents($temp))); 
        $strHeader .= "--".$strSid."\n";
        $strHeader .= "Content-Type: application/octet-stream; name=\"".$strFilesName."\"\n"; 
        $strHeader .= "Content-Transfer-Encoding: base64\n";
        $strHeader .= "Content-Disposition: attachment; filename=\"".$strFilesName."\"\n\n";
        $strHeader .= $strContent."\n\n";
        $count++;
    }


    $flgSend = @mail($strTo,$strSubject,null,$strHeader);  // @ = No Show Error //

    if($flgSend)
    {
        echo "Mail send completed.";
        $newdirectory = "applicants";
        $count = 0;
        foreach ($_FILES['myfile']['name'] as $filename)
        {
            $temp = $_FILES['myfile']['tmp_name'][$count];
            move_uploaded_file($temp, $newdirectory . '/' . $filename);
            $count++;
        }
    }
    else
    {
        echo "Cannot send mail.";
    }
?>

3 个答案:

答案 0 :(得分:1)

我会使用pathinfo来排除文件扩展名,并添加额外的timestamp以防止文件名冲突并替换现有文件。

$newdirectory = "applicants";
$count = 0;
foreach ($_FILES['myfile']['name'] as $filename)
{

    $temp = $_FILES['myfile']['tmp_name'][$count];
    $file_info = pathinfo($filename);

    // Don't you forget to have the $user available here ...
    $filename = $user . '_' . time() . '.' . $file_info['extension'];

    move_uploaded_file($temp, $newdirectory . '/' . $filename);
    $count++;
}

答案 1 :(得分:0)

move_uploaded_file() ..你可以选择文件名..

  

此函数检查以确保filename指定的文件是有效的上载文件(意味着它是通过PHP的HTTP POST上载机制上传的)。 如果文件有效,则会将其移至目的地指定的文件名。

所以你可以做到

 $newfilename='yourFileName';
 move_uploaded_file($temp, $newdirectory . '/' . $newfilename);// this will save your filename with newfilename from temp to newdirectory

答案 2 :(得分:0)

尝试使用此方法获取扩展名并重命名新文件名:

foreach ($_FILES['myfile']['name'] as $filename)
{ 
     $temp = $_FILES['myfile']['tmp_name'][$count];

     $ImageExt = substr($filename, strrpos($filename, '.'));
     $ImageExt = str_replace('.','',$ImageExt);

     $filename = "YOUR_NEW_NAME_HERE".$ImageExt;
     move_uploaded_file($temp, $newdirectory . '/' . $filename);
     count++;
}

如果文件名包含多个点(。),那么您可以使用substr(strrchr($file_name,'.'),1);pathinfo也可以为您提供帮助。