Question

我正在寻找一种方法来捕获传递给方法的实际参数，以便稍后检查它。想法是获取传递的参数然后对它执行断言。

例如：

var foo = Mock<Foo>();
var service = Mock<IService>();
service.Expect(s => s.Create(foo));
service.Create(new Foo { Currency = "USD" });
Assert(foo.Object.Currency == "USD");

或者更复杂的例子：

Foo foo = new Foo { Title = "...", Description = "..." };
var bar = Mock.NewHook<Bar>();
var service = new Mock<IService>();
service.Expect(s => s.Create(bar));

new Controller(service.Object).Create(foo);

Assert(foo.Title == bar.Object.Title);
Assert(foo.Description == bar.Object.Description);

Answer 1

我认为你正在寻找与Moq的回调相当的东西：

var foo = Mock<Foo>();
var service = Mock<IService>();
service.Setup(s => s.Create(foo.Object)).Callback((T foo) => Assert.AreEqual("USD", foo.Currency))
service.Object.Create(new Foo { Currency = "USD" });

Answer 2

如果需要对传递给对象的参数进行断言，那么您的测试似乎正在处理错误的对象。而不是声明传递给方法的参数，而是为调用正确参数的调用类编写测试。

Answer 3

另见＆＃34; Callbacks＆＃34;在Moq's Quickstart documentation中：

usort ($data, function ($a, $b)
{
    $arrayorder = array("z", "q", "9", "1", "a", "u");
    $ea = array_search(substr($a,0,1), $arrayorder );
    $eb = array_search(substr($b,0,1), $arrayorder );
    if ($ea == $eb) {
        if ( $a == $b ) {
            return 0;
        }
        else {
            return ($a< $b) ? -1 : 1;
        }
    }
    return ($ea< $eb) ? -1 : 1;
});

如何编写捕获方法参数并稍后检查它们的模拟？

3 个答案: