Question

我有一个包含大量行的文本文件，病态复制粘贴其中一些，以显示我正在使用的内容。

1 16.07.2011 kl。 17.00 OB - FCN 2 - 0 6.965
1 17.07.2011 kl。 14.00 FCM - SIF 1 - 2 5.370

2 23.07.2011 kl。 17.00 SIF - BIF 0 - 1 4.173
2 23.07.2011 kl。 19.00 FCK - OB 2 - 2 14.774
3 30.07.2011 kl。 17.00 AGF - OB 2 - 2 11.312
3 30.07.2011 kl。 19.00 FCK - FCN 2 - 0 11.076

while (fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lf\n", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10)
    int prev_goal = goal1 + goal2;
    int current;
    if(prev_goal > current) {
    printf("Runde %d var den mest målrige med %d mål\n", runde, prev_goal);
   }

我将值变为不同的变量，但是如何从每一轮中添加结果并查看哪一个目标最多？任何建议都会得到满足！谢谢:)）

Answer 1

我会假设您只关心哪一轮的目标最多，而且您不需要像@Ben建议的那样将文本文件存储在内存中。

如果是这种情况，你可以这样做：

int i, maxGoals = 0, roundWithMostGoals = 0;

for (i = 0; fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lf\n", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10; ++i)
{
    if (maxGoals < goal1 + goal2)
    {
        roundWithMostGoals = runde;
        maxGoals = goal1 + goal2;
    }
}

// Edit:
printf("The largest number of goals was %d, scored in round %d", maxGoals, roundWithMostGoals);

此代码确实存在问题。如果有两轮具有最大目标数，则只会打印第一轮。

为了避免这种情况，我们需要循环两次，这是不理想的，我建议使用其他一种将所有这些数据加载到内存中的方法。

然而，这是一个像上面那样的修改后的解决方案，即使我不认为它是最佳的：

int i, maxGoals = 0, roundWithMostGoals = 0;

// Find the maximum number of goals that was scored in any one round.
for (i = 0; fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lf\n", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10; ++i)
{
    if (maxGoals < goal1 + goal2)
    {
        maxGoals = goal1 + goal2;
    }
}

printf("The largest number of goals scored was %d.\n", maxGoals);
printf("The largest number of goals was scored in\n");

// TODO: Reposition the file stream back to the beginning or close it and then reopen it again.
// XXX Code Here XXX

// Loop through again getting all the rounds with the maximum number of goals.

for (i = 0; fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lf\n", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10; ++i)
{
    if (maxGoals == goal1 + goal2)
    {
        printf("\tRound %d\n", runde);
    }
}

但这现在循环两次，绝对不是解决问题的最佳方案。

Answer 2

你应该制作一些数组：

int goal1Array[]
int goal2Array[]
int listLength = 0;

然后，当你阅读目标时，你可以将它们添加到数组中（确保记录你要添加的数量）：

goal1Array[9] = goal1;
listLength++;

注意：您需要进行一些动态内存管理。查找c数组等。

最后，您可以循环浏览此列表以进行比较：

for (i = 0; i < listLength; i++) {
    /*compare stuff*/
}

这只是一些一般性建议，您需要付出一些努力才能在没有内存错误的情况下进行编译。

祝你好运。

Answer 3

为每个团队创建一个int数组。他们将是每个团队的总和。

然后，strcmp team1和team2的名称以及您团队的名称。然后，将目标添加到其关联的goalSum。

int goalSum[3];
goalSum[0] = 0;goalSum[1] = 0;goalSum[2] = 0


while (fscanf(ifp, "%d %d.%d.%d kl. %lf %4s - %4s %d - %d %lf\n", &runde, &dag, &month, &year, &clock, team1, team2, &goal1, &goal2, &attendance) == 10)
{

    //comparisions for the first team
    if(strcmp(team1,"nameofteam0")==0)
    {
            ++goalSum[0];
    }
    if(strcmp(team1,"nameofteam1")==0)
    {
            ++goalSum[1];
    }
    if(strcmp(team1,"nameofteam2")==0)
    {
            ++goalSum[2];
    }
    //comparisions for the second team
    if(strcmp(team2,"nameofteam0")==0)
    {
            ++goalSum[0];
    }
    if(strcmp(team2,"nameofteam1")==0)
    {
            ++goalSum[1];
    }
    if(strcmp(team2,"nameofteam2")==0)
    {
            ++goalSum[2];
    }
}

然后，比较每个团队的目标。

    const int numberOfTeams = 3;
    int winningTeam=0;

//You'll have to do the support for draws yourself.
    for(int i = 0; i<numberOfTeams; ++i)
    {
        if(sumOfGoal[i]>sumOfGoal[i+1])
        {
                winningTeam = i+1;
        }
        else
        {
                winningTeam = i+2;
        }
    }
    printf("Team%i wins!\n", winningTeam);

c组合文本文件中每行的数字

3 个答案: