SELECT
f_workorders_shipments.date,
f_inventory.id AS item_id,
f_workorders_shipments.inventory_code AS code,
f_inventory`.status,
f_inventory.type,
f_workorders.id AS order_id
FROM f_workorders
LEFT JOIN f_workorders_shipments
ON f_workorders.id = f_workorders_shipments.order_id
LEFT JOIN `f_inventory`
ON f_workorders_shipments.inventory_code = f_inventory.code
WHERE contact_id = "'.$_POST['id'].'"
AND inventory_code IS NOT NULL
ORDER BY due DESC'
答案 0 :(得分:0)
由于联接将数量乘以要检查的行,因此必须注意索引。
请为每个重要的字段制作索引,以便过滤或与其他表中的其他字段连接。
良好的索引减少了执行sql命令的时间