Question

我有preg_match_all函数：

preg_match_all('#<h2>(.*?)</h2>#is', $source, $output, PREG_SET_ORDER);

它正在按预期工作，但问题是，它preg_matches所有项目两次，并进入一个巨大的多维数组，例如，如预期的那样，preg_matched所有11项需要，但两次，并进入一个多维数组：< / p>

Array
(
    [0] => Array
        (
            [0] => <h2>10. <em>Cruel</em> by St. Vincent</h2>
            [1] => 10. <em>Cruel</em> by St. Vincent
        )

    [1] => Array
        (
            [0] => <h2>9. <em>Robot Rock</em> by Daft Punk</h2>
            [1] => 9. <em>Robot Rock</em> by Daft Punk
        )

    [2] => Array
        (
            [0] => <h2>8. <em>Seven Nation Army</em> by the White Stripes</h2>
            [1] => 8. <em>Seven Nation Army</em> by the White Stripes
        )

    [3] => Array
        (
            [0] => <h2>7. <em>Do You Want To</em> by Franz Ferdinand</h2>
            [1] => 7. <em>Do You Want To</em> by Franz Ferdinand
        )

    [4] => Array
        (
            [0] => <h2>6. <em>Teenage Dream</em> by Katie Perry</h2>
            [1] => 6. <em>Teenage Dream</em> by Katie Perry
        )

    [5] => Array
        (
            [0] => <h2>5. <em>Crazy</em> by Gnarls Barkley</h2>
            [1] => 5. <em>Crazy</em> by Gnarls Barkley
        )

    [6] => Array
        (
            [0] => <h2>4. <em>Kids</em> by MGMT</h2>
            [1] => 4. <em>Kids</em> by MGMT
        )

    [7] => Array
        (
            [0] => <h2>3. <em>Bad Romance</em> by Lady Gaga</h2>
            [1] => 3. <em>Bad Romance</em> by Lady Gaga
        )

    [8] => Array
        (
            [0] => <h2>2. <em>Pumped Up Kicks</em> by Foster the People</h2>
            [1] => 2. <em>Pumped Up Kicks</em> by Foster the People
        )

    [9] => Array
        (
            [0] => <h2>1. <em>Paradise</em> by Coldplay</h2>
            [1] => 1. <em>Paradise</em> by Coldplay
        )

    [10] => Array
        (
            [0] => <h2>Song That Get Stuck In Your Head YouTube Playlist</h2>
            [1] => Song That Get Stuck In Your Head YouTube Playlist
        )

)

如何将此数组转换为简单数组并且没有这些重复项？非常感谢你。

Answer 1

你将永远得到一个多维数组，但是，你可以接近你想要的东西：

if (preg_match_all('#<h2>(.*?)</h2>#is', $source, $output, PREG_PATTERN_ORDER))
    $matches = $output[0]; // reduce the multi-dimensional array to the array of full matches only

如果你根本不想要子匹配，那么使用非捕获分组：

if (preg_match_all('#<h2>(?:.*?)</h2>#is', $source, $output, PREG_PATTERN_ORDER))
    $matches = $output[0]; // reduce the multi-dimensional array to the array of full matches only

请注意，对preg_match_all的调用是使用PREG_PATTERN_ORDER而不是PREG_SET_ORDER：

PREG_PATTERN_ORDER对结果进行排序，以便$ matches [0]是一个数组   完整模式匹配，$ matches [1]是一个匹配的字符串数组   第一个带括号的子模式，依此类推。

PREG_SET_ORDER对结果进行排序，以便$ matches [0]是第一个数组   匹配集，$ matches [1]是第二组匹配的数组，和   等等。

请参阅：http://php.net/manual/en/function.preg-match-all.php

Answer 2

使用

#<h2>(?:.*?)</h2>#is

作为你的正则表达式。如果您使用非捕获组（?:表示的话），则反向引用将不会显示在数组中。

preg_match_all成简单数组

2 个答案: