Question

我正在考虑使用Quartz安排我的应用程序，但在所有情况下，作业触发器似乎是一次性活动，并且对触发器的更改需要重新部署应用程序才能生效。
有没有办法让工作触发器检查工作计划的更改，而无需重新部署代码？谢谢，

Answer 1

捕获一些用户驱动的事件，例如更新文本值，例如用于安排作业的cron字符串
找到并取消预定/删除旧作业并触发。

使用新触发器再次安排作业。

public static <T> T scheduleCronJob(Class<T> clazz, String cronString, String uid){
    try{            
        if(cronString == null){
            throw new CronStringConfigurationException();
        }

        String jobGroupName = "cronJobsGroup";
        String jobName = "cronJob" + uid;
        String triggerGroupName = "cronTriggers";
        String triggerName = "triggerFor" + uid;

        JobDetail jobDetail = new JobDetail(jobName, jobGroupName, clazz);

        CronTrigger trigger = new CronTrigger(
                triggerName, triggerGroupName, 
                jobName, jobGroupName, 
                cronString);

        JobDataMap jobDataMap = new JobDataMap();
        jobDetail.setJobDataMap(jobDataMap);

        getScheduler().scheduleJob(jobDetail, trigger);
    } catch(Exception e){
    // print error message, throw stack trace
    }
    return null;
}

public static void reloadCronJob(Class clazz, String cronString, String uid) throws SystemException, ParseException, SchedulerException, 
    CronStringConfigurationException, PortalException{
    // locate the job 
    String jobGroupName = "cronJobs";
    String jobName = "jobFor" + uid;

    if(cronString == null){
        throw new CronStringConfigurationException();
    }

    JobDetail jobDetail = null;
    Class<?> jobClass = null;

    // remove the old job/trigger if it exists
    try{
        jobDetail = scheduler.getJobDetail(jobName, jobGroupName);
        if(jobDetail != null){
            jobClass = jobDetail.getJobClass();
        }
        scheduler.deleteJob(jobName, jobGroupName);
    } catch(Exception e){
        e.printStackTrace();
    }

    if(jobClass == null){
        jobClass = clazz;
    }

    // create a new trigger
    scheduleCronJob(jobClass, expandoColumnName, uid);

    System.out.println("(re)scheduled job " + jobName + " using new cron string " + cronString);
}

改变石英作业计划

1 个答案: