Question

使用以下命令生成表格时遇到问题：

php symfony doctrine:insert-sql

它返回以下错误：

>> doctrine  creating tables


  Class "Complaint" must be a child class of Doctrine_Record


PHP Fatal error:  Call to a member function evictAll() on a non-object in D:\Internet\PHP\ijzerleeuw_bezoekrapporten\lib\vendor\symfony\lib\plugins\sfDoctri
nePlugin\lib\vendor\doctrine\Doctrine\Connection.php on line 1239
PHP Stack trace:
PHP   1. {main}() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\symfony:0
PHP   2. include() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\symfony:14
PHP   3. sfDatabaseManager->shutdown() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\lib\vendor\symfony\lib\database\sfDatabaseManager.class.php:0
PHP   4. sfDoctrineDatabase->shutdown() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\lib\vendor\symfony\lib\database\sfDatabaseManager.class.php:134
PHP   5. Doctrine_Manager->closeConnection() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\database\sfDoctr
ineDatabase.class.php:165
PHP   6. Doctrine_Connection->close() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\vendor\doctrine\Doctrin
e\Manager.php:580
PHP   7. Doctrine_Connection->clear() D:\Internet\PHP\ijzerleeuw_bezoekrapporten\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\vendor\doctrine\Doctrin
e\Connection.php:1268

这是我的schema.yml，我用它来生成模型（php symfony doctrine：build-mdeol）：

InspectionReport:
  actAs: { Timestampable: ~ }
  columns:
    customer_id:    { type: integer(5), notnull: true }
    username:       { type: string(255), notnull: true }
    start_time:     { type: string(5) }
    end_time:       { type: string(5) }
    type:           { type: string(5) }
    reason:         { type: string(4) }
    contact:        { type: string(5) }
    subject:        { type: string(5) }
    remarks:        { type: string(5000) }
    emailaddresses: { type: string(5) }
  relations:
    Complaints:
      class: Complaint
      refClass: ComplaintInspectionReport
      local: id
      foreign: complaint_id
    Reviews:
      class: Review
      refClass: ReviewInspectionReport
      local: id
      foreign: review_id

ComplaintInspectionReport:
  columns:
    complaint_id:  { type: integer(4), primary: true }
    inspection_report_id: { type: integer, primary: true }
  relations:
    Complaint:  { onDelete: CASCADE, local: complaint_id, foreign: id }
    InspectionReport: { onDelete: CASCADE, local: inspection_report_id, foreign: id }

ReviewInspectionReport:
  columns:
    review_id:  { type: integer, primary: true }
    inspection_report_id: { type: integer, primary: true }
  relations:
    Review:  { onDelete: CASCADE, local: review_id, foreign: id }
    InspectionReport: { onDelete: CASCADE, local: inspection_report_id, foreign: id }

Complaint:
  columns:
    id:            { type: integer, notnull: true }
    description:   { type: string(32), notnull: true }
    contact:       { type: string(32) }
    remark:        { type: string(50) }

Review:
  columns:
    id:            { type: integer, notnull: true }
    description:   { type: string(32), notnull: true }
    contact:       { type: string(32) }
    remark:        { type: string(50) }
    grade:         { type: string(1) }
    email_address: { type: string(32) }

我从模型/模式生成的schema.sql（php symfony doctrine：build-sql）：

CREATE TABLE complaint (id BIGINT AUTO_INCREMENT, description VARCHAR(32) NOT NULL, contact VARCHAR(32), remark VARCHAR(50), PRIMARY KEY(id)) ENGINE = INNODB;
CREATE TABLE complaint_inspection_report (complaint_id INT, inspection_report_id BIGINT, PRIMARY KEY(complaint_id, inspection_report_id)) ENGINE = INNODB;
CREATE TABLE inspection_report (id BIGINT AUTO_INCREMENT, customer_id BIGINT NOT NULL, username VARCHAR(255) NOT NULL, start_time VARCHAR(5), end_time VARCHAR(5), type VARCHAR(5), reason VARCHAR(4), contact VARCHAR(5), subject VARCHAR(5), remarks TEXT, emailaddresses VARCHAR(5), created_at DATETIME NOT NULL, updated_at DATETIME NOT NULL, PRIMARY KEY(id)) ENGINE = INNODB;
CREATE TABLE review (id BIGINT AUTO_INCREMENT, description VARCHAR(32) NOT NULL, contact VARCHAR(32), remark VARCHAR(50), grade VARCHAR(1), email_address VARCHAR(32), PRIMARY KEY(id)) ENGINE = INNODB;
CREATE TABLE review_inspection_report (review_id BIGINT, inspection_report_id BIGINT, PRIMARY KEY(review_id, inspection_report_id)) ENGINE = INNODB;
ALTER TABLE complaint_inspection_report ADD CONSTRAINT complaint_inspection_report_complaint_id_complaint_id FOREIGN KEY (complaint_id) REFERENCES complaint(id) ON DELETE CASCADE;
ALTER TABLE complaint_inspection_report ADD CONSTRAINT ciii FOREIGN KEY (inspection_report_id) REFERENCES inspection_report(id) ON DELETE CASCADE;
ALTER TABLE review_inspection_report ADD CONSTRAINT riii FOREIGN KEY (inspection_report_id) REFERENCES inspection_report(id) ON DELETE CASCADE;
ALTER TABLE review_inspection_report ADD CONSTRAINT review_inspection_report_review_id_review_id FOREIGN KEY (review_id) REFERENCES review(id) ON DELETE CASCADE;

如果我手动运行SQL它工作正常，但是当使用doctrine：insert-sql时它会返回错误。

我正在考虑我的架构中的错误，但似乎无法掌握它。或许它可能完全不同。

Answer 1

我错了，我刚刚生成了类，并没有尝试加载sql。

实际上你几乎没有错误：

你不应该为表定义一个列id，只要你不需要它来主键，不增加等等。否则会给Doctrine带来麻烦
对于每个中间人表（ComplaintInspectionReport＆amp; ReviewInspectionReport），您无需重新定义relations。如果在父类中正确定义它们，则不需要它们
注意integer类型。 Doctrine将始终使用integer，但是如果您定义一个带有integer(4)的外来导致由Doctrine自动生成的id，则插入sql时该关系将失败。因为一边是integer，另一边是integer(4)。
最后，请注意local中定义的InspectionReport密钥。您使用id两次，但您必须为中间表定义本地密钥，而不是当前密钥。因此，您必须为两者设置inspection_report_id。

这是固定架构：

InspectionReport:
  actAs: { Timestampable: ~ }
  columns:
    customer_id:    { type: integer(5), notnull: true }
    username:       { type: string(255), notnull: true }
    start_time:     { type: string(5) }
    end_time:       { type: string(5) }
    type:           { type: string(5) }
    reason:         { type: string(4) }
    contact:        { type: string(5) }
    subject:        { type: string(5) }
    remarks:        { type: string(5000) }
    emailaddresses: { type: string(5) }
  relations:
    Complaints:
      class: Complaint
      refClass: ComplaintInspectionReport
      local: inspection_report_id
      foreign: complaint_id
    Reviews:
      class: Review
      refClass: ReviewInspectionReport
      local: inspection_report_id
      foreign: review_id

ComplaintInspectionReport:
  columns:
    complaint_id:  { type: integer, primary: true }
    inspection_report_id: { type: integer, primary: true }

ReviewInspectionReport:
  columns:
    review_id:  { type: integer, primary: true }
    inspection_report_id: { type: integer, primary: true }

Complaint:
  columns:
    description:   { type: string(32), notnull: true }
    contact:       { type: string(32) }
    remark:        { type: string(50) }

Review:
  columns:
    description:   { type: string(32), notnull: true }
    contact:       { type: string(32) }
    remark:        { type: string(50) }
    grade:         { type: string(1) }
    email_address: { type: string(32) }

在尝试重新插入sql之前，请不要忘记清除缓存。

类必须是php symfony doctrine上的Doctrine_Record错误的子类：insert-sql

1 个答案: