鉴于以下两个表:
Person table
id (pk)
first
middle
last
age
Address table
id(pk)
person_id (fk person.id)
street
city
state
zip
如何创建一个SQL语句,返回邮政编码为97229的人的所有信息?
答案 0 :(得分:28)
Select * from people p, address a where p.id = a.person_id and a.zip='97229';
或者你必须尝试使用JOIN
这是一种更有效,更好的方法,因为Gordon Linoff在下面的评论中也说你需要学习这个。
SELECT p.*, a.street, a.city FROM persons AS p
JOIN address AS a ON p.id = a.person_id
WHERE a.zip = '97299';
此处p.*
表示它将显示PERSONS表的所有列。
答案 1 :(得分:4)
您需要加入两个表:
select p.id, p.first, p.middle, p.last, p.age,
a.id as address_id, a.street, a.city, a.state, a.zip
from Person p inner join Address a on p.id = a.person_id
where a.zip = '97229';
这将选择两个表中的所有列。您当然可以通过在select
子句中选择不同的列来限制它。
答案 2 :(得分:1)
就像那样:
SELECT p.*, a.street, a.city FROM persons AS p
JOIN address AS a ON p.id = a.person_id
WHERE a.zip = '97299'
答案 3 :(得分:1)
首先从人员表中选择所有记录,然后将所有这些记录加入另一个表'地址'...现在你已经记录了所有在地址表中有地址的人...所以最后用邮编过滤你的记录
select * from Person as P inner join Address as A on
P.id = A.person_id Where A.zip='97229'
答案 4 :(得分:0)
select P.*,
A.Street,
A.City,
A.State
from Preson P
inner join Address A on P.id=A.Person_id
where A.Zip=97229
Order by A.Street,A.City,A.State