Question

我要做的是找到所有在前一天购买Series X或Series A小部件的客户，只要这是他们第一次从中购买小部件。如果他们购买了多个符合条件的小部件Series X获得排名，我只能找回它的记录。希望这是有道理的，所以这里是数据

[customers]
c_id     cp_id
--------------
1        cp1
2        cp2
3        cp3
4        cp4
5        cp5
6        cp6
7        cp7
8        cp8
9        cp9
10       cp10

[widget_orders - c_id maps to c_id in customers]
c_id    w_sku   o_date
----------------------
1       w1      2012-10-10
2       w1      2012-10-10
2       w2      2012-10-10
3       w1      2012-10-10
3       w2      2012-10-10
4       w1      2012-10-10
4       w2      2012-10-10
5       w1      2012-10-10
5       w2      2012-10-10
6       w1      2012-10-10
6       w2      2012-10-10
7       w2      2012-10-10
8       w1      2012-10-10
9       w3      2012-10-10

[widgets - w_sku maps to w_sku in widget_orders]
w_sku   w_series
------------------
w1      Series A
w2      Series X
w3      Series C

[customer_data - c_id maps to c_id in customers]
cp_id   seriesA_fPurch  seriesX_fPurch
--------------------------------------
cp3     
cp4     2012-09-15
cp5                     2012-09-15
cp6     2012-09-15      2012-09-15
cp7                     2012-09-15  
cp8     2012-09-15

以下是我想要取消忽略（）

中描述的数据

cp_id   series
--------------
cp1     Series A (bought series A and had NO prior purchase history)
cp2     Series X (bought both series, but X has rank - no purchase history)
cp3     Series X (bought both series, but X has rank - has purchase history recors albeit not for these)
cp4     Series X (bought both series, but X has rank - already had A history anyways)
cp5     Series A (bought both series, although X has rank they had previously bought series X)

以下人员未在结果中显示

cp6 - they had previously bought both series
cp7 - bought a series x, but had in the past
cp8 - bought a series a, but had in the past
cp9 - bought a widget in neither series
cp10 - didnt buy anything

希望所有这些都有意义，有人可以帮助我在这里！

所以总结一下逻辑，或许可以更明确地定义它，我将如何描述需要以步进式方式发生的事情

1) Find all customers who have no matching records in the customer_data table
2) Find all customers who have a null value in either *purch column in the customer_data table
3) Combine these results together
4) Take the results and find the customers who made a purchase yesterday
5) Take the results and find the customers who purchased Series A or Series X
6) Take the results and do the following
    6a) If the purchase was Series A and they have a value for series A purch already drop them from results
    6b) If the purchase was Series X and they have a value for series X purch already drop them from results
7) Take the results and remove duplicate records based on the cp_id - Series X takes presedence over Series A

Answer 1

我不确定我完全理解你的要求，但请尝试：

SELECT cp_id, w_series
FROM (
SELECT rank() over (partition BY wo."c_id" ORDER BY decode(w."w_series",'Series X',1,'Series A',2)) rank,
       wo."c_id" c_id,
       c."cp_id" cp_id,
       w."w_series" w_series
FROM widget_orders wo JOIN widgets w ON wo."w_sku"=w."w_sku"
  JOIN customers c on c."c_id"=wo."c_id"
LEFT OUTER JOIN customer_data cd ON c."cp_id" = cd."cp_id"
WHERE  w."w_series" IN ('Series A', 'Series X')
  AND  trunc(wo."o_date") = trunc(sysdate)-1
  AND ( (cd."seriesA_fPurch" IS NULL AND w."w_series"='Series A')
     OR (cd."seriesX_fPurch" IS NULL AND w."w_series"='Series X'))
  )
WHERE rank = 1

Here是一个小提琴

说明：
根据步骤数字 -
1）+ 2）在LEFT OUTER JOIN + cd."seriesA_fPurch" IS NULL条件+ cd."seriesX_fPurch" IS NULL条件下完成，因为它也会找到那些没有记录并将空值放入其中的人。
3）明显...
4）trunc(wo."o_date") = trunc(sysdate)-1条件
5）w."w_series" IN ('Series A', 'Series X')
6）(cd."seriesA_fPurch" IS NULL AND w."w_series"='Series A') OR (cd."seriesX_fPurch" IS NULL AND w."w_series"='Series X')条件
7）给出记录的等级和WHERE rank = 1条件

Oracle / SQL - 多表连接逻辑 - 不确定如何用它来表达它

1 个答案: