假设我有两个名为Book
和Library
的课程如下:
var Book = function(title, author)
{
this.title = title;
this.author = author;
};
和
var Library = function()
{
var dbName = 'test';
this.getLibrary = function() {
return JSON.parse(window.localStorage.getItem(dbName));
};
this.save = function(library) {
window.localStorage.setItem(dbName, JSON.stringify(library));
};
}
Library.prototype.addBook = function(book) {
var library = this.getLibrary();
library.push(book);
this.save(library);
return library;
};
Library.prototype.removeBook = function(book) {
var library = this.getLibrary();
// Find and delete the right book
this.save(library);
return library;
};
我的问题是:如何使用QUnit对Library
类进行单元测试以进行真正的原子和独立测试?
我写了这个测试功能,但它并没有让我满意。它似乎不是非常原子和独立的,因为它混合了我认为应该独立测试的几个函数。我想知道是否有更好的方法,或者我已经测试好了。
test("test", function() {
var library = new Library();
deepEqual(library.getLibrary(), []);
// Add book1
var book1 = new Book("A book", "An author");
deepEqual(library.addBook(book1), [book1]);
deepEqual(library.getLibrary(), [book1]);
// Add book2
book2 = new Result("A new book", "Another author");
deepEqual(library.addBook(book2), [book2, book1]);
deepEqual(library.getLibrary(), [book2, book1]]);
// Remove book1
deepEqual(library.removeResult(book1), [book2]);
deepEqual(library.getLibrary(), [book2]);
// Remove book2
deepEqual(library.removeResult(book2), []);
deepEqual(library.getLibrary(), []);
});
答案 0 :(得分:3)
避免编写依赖于您正在测试的单元的内部状态的“综合”测试。对特定行为进行细粒度测试,而不是状态:
test("addBooksReturnsLibrary", function(){
var l = new Library();
l.addBook(new Book(...));
l.addBook(new Book(...));
var addBooksRetval = l.addBook(new Book(...));
deepEqual(addBooksRetval, l.getLibrary();
});
test("libraryContainsAddedBook"), function() {
var l = new Library();
var b = new Book(...);
l.addBook(b);
notEqual(-1, library.indexOf(b));
});
// etc and so forth
deepEqual
的大量使用似乎更像是一种测试气味。如果您确实需要按照特定顺序在图书馆中存放图书,我会说最好是专门测试那些订购限制。