Question

我有一个Windows应用程序，它接收文本框中的数据并将它们写入随机生成的文本文件，有点保存日志。然后有这个列表框列出了所有这些单独的日志文件。我想要做的是让另一个列表框显示所选文件的文件信息，在按钮列表后选择的文本文件的第2，第7，第12，......，（2 + 5n）行信息'被点击。怎么可能这样做？

我更新第一个列表框的代码是：

private void button2_Click(object sender, EventArgs e)
    {
        listBox1.Items.Clear();

        DirectoryInfo dinfo = new DirectoryInfo(@"C:\Users\Ece\Documents\Testings");
        // What type of file do we want?...

        FileInfo[] Files = dinfo.GetFiles("*.txt");
        // Iterate through each file, displaying only the name inside the listbox...

        foreach (FileInfo file in Files) 
        {
            listBox1.Items.Add(file.Name + "         " +file.CreationTime); 
        }

    }

Answer 1

在SelectedIndexChanged事件中，您想要获取所选项目。我不建议在另一个列表框中显示第二部分，但我相信如果你需要，你可以从下面的例子中找出它。我个人有一个richTextBox，只是读到那里的文件：

//Get the FileInfo from the ListBox Selected Item
FileInfo SelectedFileInfo = (FileInfo) listBox.SelectedItem;  

//Open a stream to read the file  
StreamReader FileRead = new StreamReader(SelectedFileInfo.FullName);

//Read the file to a string
string FileBuffer = FileRead.ReadToEnd();

//set the rich text boxes text to be the file
richTextBox.Text = FileBuffer;

//Close the stream so the file becomes free!
FileRead.Close();

或者如果你坚持使用ListBox，那么：

//Get the FileInfo from the ListBox Selected Item
FileInfo SelectedFileInfo = (FileInfo) listBox.SelectedItem;   

//Open a stream to read the file 
StreamReader FileRead = new StreamReader(SelectedFileInfo.FullName);

string CurrentLine = "";
int LineCount = 0;

//While it is not the end of the file
while(FileRead.Peek() != -1)
  {
  //Read a line
  CurrentLine = FileRead.ReadLine();

  //Keep track of the line count
  LineCount++;

  //if the line count fits your condition of 5n + 2
  if(LineCount % 5 == 2)
    {
    //add it to the second list box
    listBox2.Items.Add(CurrentLine);
    }
  }

//Close the stream so the file becomes free!
FileRead.Close();

如何获取在listBox中选择的文件信息？

1 个答案: