不能使用ghci推断的类型签名来返回Sing(d :: Symbol)的函数

时间:2012-09-24 16:45:49

标签: haskell

我试图恢复值类型中使用的Symbol

{-# LANGUAGE GADTs #-}
{-# LANGUAGE KindSignatures #-}
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE ScopedTypeVariables #-}
module Temp where

import GHC.TypeLits

data Temp (d :: Symbol) (a :: *) where 
  T :: a -> Temp d a

{-
description :: SingI Symbol d => Temp d a -> Sing Symbol d
-}
description (_ :: Temp d a) = (sing :: Sing d)

这在ghci(版本7.6.1)中加载正常:

% ghci
GHCi, version 7.6.1: http://www.haskell.org/ghc/  :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer-gmp ... linking ... done.
Loading package base ... linking ... done.
Prelude> :l Temp
[1 of 1] Compiling Temp             ( Temp.hs, interpreted )
Ok, modules loaded: Temp.
*Temp> :t description
description :: SingI Symbol d => Temp d a -> Sing Symbol d

但是,如果我尝试在模块本身中使用ghci推断的类型(取消注释Temp.h中的行),我会收到以下错误:

Temp.hs:14:16:
    `SingI' is applied to too many type arguments
    In the type signature for `description':
      description :: SingI Symbol d => Temp d a -> Sing Symbol d

这对我来说很有意义,因为Sing and SingI seem to take a single parameter in the documentation

description

的正确类型签名是什么?

1 个答案:

答案 0 :(得分:2)

好的,通过一些关于:

的讨厌
description :: SingI d => Temp d a -> Sing d

看起来有一些时髦的重写,但现在还不错。