以下代码尝试测试boost::mpl::or_
和boost::mpl::and_
的短路行为:
#include <vector>
#include <boost/mpl/eval_if.hpp>
#include <boost/mpl/identity.hpp>
#include <boost/mpl/or.hpp>
#include <boost/mpl/and.hpp>
#include <boost/type_traits/is_scalar.hpp>
// Dummy is forward declared and never defined
template <class T> class dummy;
// If T is a scalar evaluates to T without trying to compute the result of
// boost::mpl::is_scalar< dummy<T>, otherwise it fails at compile time.
template <class T>
class testOr
: public boost::mpl::eval_if<
boost::mpl::or_< boost::is_scalar<T>, boost::is_scalar< dummy<T> > >,
boost::mpl::identity<T>,
dummy<T>
>
{};
// If T is not a scalar evaluates to T without trying to compute the result of
// boost::mpl::is_scalar< dummy<T>, otherwise it should fail at compile time.
template <class T>
class testAnd
: public boost::mpl::eval_if<
// It appears that is_scalar< dummy<T> > is not instantiated and the operation
// evaluates to false
boost::mpl::and_< boost::is_scalar<T>, boost::is_scalar< dummy<T> > >,
dummy<T>,
boost::mpl::identity<T>
>
{};
int main() {
static_assert(boost::is_same< testOr< double >::type, double>::type::value,"Fails at compile time");
// The following line causes failures at compile time due to incomplete type definition
//static_assert(boost::is_same< testOr< std::vector<double> >::type, double>::type::value,"Fails at compile time");
static_assert(boost::is_same< testAnd< std::vector<double> >::type, std::vector<double> >::type::value,"Fails at compile time");
// The following should cause failure at compile time due to incomplete type definition, but works instead!
static_assert(boost::is_same< testAnd< double >::type , double >::type::value,"Fails at compile time");
return 0;
}
虽然由于类型定义不完整,我希望这段代码在编译时失败,但它实际上有效:
>icpc --version
icpc (ICC) 12.1.3 20120212
Copyright (C) 1985-2012 Intel Corporation. All rights reserved.
>icpc -gcc-name=gcc-4.5 -std=c++0x -o ex-4.0.x ex-4.0.cc
所以,我想了解的一点是:
boost::mpl::or_
和boost::mpl::and_
评估其参数的方式是否存在不一致,或者很可能是我无法捕获的代码中存在错误?
答案 0 :(得分:2)
为什么你认为or_
的第二个参数不会被评估? is_scalar
可以与未定义的类型一起使用。
例如,在这种情况下,您也会收到错误。
// If T is not a scalar evaluates to T without trying to compute the result of
// boost::mpl::is_scalar< dummy<T>, otherwise it should fail at compile time.
template <class T>
class testAnd
: public boost::mpl::eval_if<
// It appears that is_scalar< dummy<T> > is not instantiated and the operation
// evaluates to false
boost::mpl::and_< boost::is_scalar<T>, boost::is_scalar< dummy<T> > >,
boost::mpl::identity<T>,
dummy<T>
>
{};
由于boost::is_scalar<T>
为真,但boost::is_scalar<dummy<T>>
在您的情况下为假,所以。
看。 http://liveworkspace.org/code/a792e18ca16a0410a67a6eee8c550bd9
答案 1 :(得分:2)
您的想法中存在逻辑错误 - ||
将短路 iif 第一个参数评估为 true
。 is_scalar<std::vector<double>>
是false
,意味着需要评估第二个参数。相反,如果第一个参数为&&
,false
将会短路,如上所述。