Question

如果我的代码如下：

if($seconds < 60)
  $interval = "$seconds seconds ago";
else
 if($seconds < 3600)
     $interval = floor($seconds / 60) . "minutes ago";
else
    if($seconds < 86400)
         $interval = floor($seconds / 3600) . "hours ago";
    else
         $interval = floor($seconds / 86400) . "days ago";

我怎么能摆脱它说的话：

1天前。 1年前 1分钟前。 1小时前。

谢谢：）

Answer 1

可以用三元运算符非常简洁地完成：

if($seconds < 60) {
    $interval = "$seconds second" . (($seconds != 1) ? "s" : "") . " ago";
} else {
    if($seconds < 3600) {
        $minutes = floor($seconds / 60);
        $interval = "$minutes minute" . (($minutes > 1) ? "s" : "") . " ago";
    } else {
        if($seconds < 86400) {
            $hours =  floor($seconds / 3600);
            $interval = "$hours hour" . (($hours > 1) ? "s" : "") . " ago";
        } else {
            $days = floor($seconds / 86400);
            $interval = "$days day" . (($days > 1) ? "s" : "") . " ago";
        }
    }
}

Answer 2

如果您的应用是国际性的并使用gettext扩展程序，则可以执行以下操作：

sprintf(ngettext('%d minute', '%d minutes', $amount), $amount);

您可以为它创建一个包装函数：

function pluralize($singular, $plural, $num) {
  return sprintf(ngettext($singular, $plural, $num), $num);
}

这是最好的方式。

Answer 3

又一种解决方案。

if($seconds < 60)
  $interval = "$seconds second";
 else
   if($seconds < 3600)
     $interval = floor($seconds / 60) . " minute";
   else
     if($seconds < 86400)
       $interval = floor($seconds / 3600) . " hour";
     else
       $interval = floor($seconds / 86400) . " day";
$interval .= (reset(explode(" ", $interval)) != 1 ? "s" : "")." ago";

Answer 4

$time = "120";
$array = array("second" => 1,
               "minute" => 60,
               "hour" => 60,
               "day" => 24,
               "year" => 365);
$old_time = 0;
$old_type = false;

// Loop through each type
foreach($array as $type => $seconds)
{
    // Divide
    $time = floor($time/$seconds);
    // If it went into a value lower than 0, stop dividing
    if($time < 1)
    {
        $time = $old_time;
        $type = $old_type;
        break;
    }
    else
    {
        // Continue dividing.
        $old_time = $time;
        $old_type = $type;
    }
}
if($time == 1)
{
    $interval = $time . " ". $type . " ago";
}
else
{
    $interval = $time ." " . $type . "s ago";
}
echo $interval;

这将划分所有可能的时间类型，并给出一个不会将其转换为分数的时间类型。通过将数值与类型分开，我们可以测试数字是否= = 1，并更正单词。

Answer 5

if ($interval < 60) {
    $unit = 'Second';
} else if ($interval < 1440) {
    $unit = 'Minute'; $interval /= 60;
} else if ($interval < 86400) {
    $unit = 'Hour'; $interval /= 1440;
} else {
    $unit = 'Day'; $interval /= 86400;
}
$interval = intval($interval);
$interval = "$interval  $unit" . ($interval == 1 ? '' : 's') . " ago";

Answer 6

这是一个用于获取“1个月，2周和30秒前”字符串的通用PHP片段。

$timeUnits = array("month" => 2592000,
                  "week" => 604800,
                  "day" => 86400,
                  "hour" => 3600,
                  "minute" => 60,
                  "second" => 1);

$tmpSeconds = $seconds;

$timeAgoStrings = array();

foreach ($timeUnits as $name => $numOfSeconds) {
   if ($seconds > $numOfSeconds) {
      $val = floor($tmpSeconds / $numOfSeconds);
      $agoStr = ($val > 1) ? $name."s" : $name;
      $timeAgoStrings[] = "$val $agoStr";
      $tmpSeconds = $tmpSeconds - $val; // cut the used time units off our tmpSeconds variable
   }
}
//check if we have more than one string - in case we do then we will pop the last val and add an "and" prefix before the last val instead of a comma
if (count($timeAgoStrings) > 1) {
   $lastString = array_pop($timeAgoStrings);
   $timeAgoStr = implode(", ",$timeAgoStrings)." and $lastString ago";
} else {
   $timeAgoStr = $timeAgoStrings[0]." ago";
}

Answer 7

做数学。

else if($seconds < 120)
     $interval = "1 minute ago";
else if($seconds < 172800)
     $interval = "1 day ago"

等

防止“一小时”“一小时”“一天”

7 个答案: