如何在C ++中读取.proto格式的二进制文件?

时间:2012-09-08 14:14:54

标签: c# c++ protocol-buffers

我有一个使用C#创建的.bin文件,带有protobuf库和以下类:

[ProtoContract]
class TextureAtlasEntry
{
    [ProtoMember(1)]
    public int Height { get; set; }

    [ProtoMember(2)]
    public string Name { get; set; }

    [ProtoMember(3)]
    public int Width { get; set; }

    [ProtoMember(4)]
    public int X { get; set; }

    [ProtoMember(5)]
    public int Y { get; set; }
}

关联的.proto文件看起来像

package TextureAtlasSettings;           // Namespace equivalent

message TextureAtlasEntry               
{
    required int32 Height = 1;
    required string Name = 2;
    required int32 Width = 3;
    required int32 X = 4;
    required int32 Y = 5;
}

已通过protoc.exe解析生成TextureAtlasSettings.pb.cc和TextureAtlasSettings.pb.h。对于C ++。

我想用C ++读取生成的二进制文件,所以我尝试了以下代码

TextureAtlasSettings::TextureAtlasEntry taSettings;

ifstream::pos_type size;
char *memblock;

ifstream file("Content\\Protobuf\\TextureAtlas0.bin", ios::in | ios::binary);

if (file.is_open())
{
    size = file.tellg();
    memblock = new char[size];
    file.seekg(0, ios::beg);
    file.read(memblock, size);
    file.close();

    fstream input(&memblock[0], ios::in | ios::binary);

    if (!taSettings.ParseFromIstream(&file)) 
    {
        printf("Failed to parse TextureAtlasEntry");
    }

    delete[] memblock;
}

上面的代码将始终触发printf。如何正确读取文件以便反序列化?

2 个答案:

答案 0 :(得分:3)

您展示的模型实际上代表protobuf-net,可选字段(其中几个默认值为零)。因此,可能会省略任何零,这会导致c ++读取器拒绝该消息(因为.proto会根据需要将其列出)。

获取代表.proto:

string proto = Serializer.GetProto<YourType>();

或者在c#中使它们“必需”:

[ProtoMember(3, IsRequired = true)]

(等)

答案 1 :(得分:1)

这样做应该足够了:

TextureAtlasSettings::TextureAtlasEntry taSettings;

ifstream file("Content\\Protobuf\\TextureAtlas0.bin", ios::in | ios::binary);

if (file.is_open())
{
    if (!taSettings.ParseFromIstream(&file)) 
    {
        printf("Failed to parse TextureAtlasEntry");
    }
}