您好我正在研究用户管理系统。我显示了来自db的所有记录，并且成功执行了添加，编辑和删除操作。现在我需要在主页中显示只有来自Mysql表的活动记录。我的管理控制中有2个链接，一个是激活，另一个是停用。如果我点击激活，记录将显示在主页上，停用意味着记录将隐藏在主页中。我用
插入了字段状态datatype enum('active','deactive')`.
我的编码如下。在编码我需要的变化？
的index.php：
<form method="post">
<table>
<tr>
<td>Title:</td>
<td><input type="text" name="title" /></td>
</tr>
<tr>
<td>Author</td>
<td><input type="text" name="author" /></td>
</tr>
<tr>
<td>Publisher Name</td>
<td><input type="text" name="name" /></td>
</tr>
<tr>
<td>Copyright Year</td>
<td><input type="text" name="copy" /></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="submit" value="add" /></td>
</tr>
</table>
<?php
if (isset($_POST['submit']))
{
include 'db.php';
$title=$_POST['title'] ;
$author= $_POST['author'] ;
$name=$_POST['name'] ;
$copy=$_POST['copy'] ;
mysql_query("INSERT INTO `books`(Title,Author,PublisherName,CopyrightYear)
VALUES ('$title','$author','$name','$copy')");
}
?>
</form>
<table border="1">
<?php
include("db.php");
$result=mysql_query("SELECT * FROM books");
while($test = mysql_fetch_array($result))
{
$id = $test['BookID'];
echo "<tr align='center'>";
echo"<td><font color='black'>" .$test['BookID']."</font></td>";
echo"<td><font color='black'>" .$test['Title']."</font></td>";
echo"<td><font color='black'>". $test['Author']. "</font></td>";
echo"<td><font color='black'>". $test['PublisherName']. "</font></td>";
echo"<td><font color='black'>". $test['CopyrightYear']. "</font></td>";
echo"<td> <a href ='view.php?BookID=$id'>Edit</a>";
echo"<td> <a href ='view.php?BookID=$id'>Activate</a>";
echo"<td> <a href ='view.php?BookID=$id'>Deactivate</a>";
echo"<td> <a href ='del.php?BookID=$id'><center>Delete</center></a>";
echo "</tr>";
}
mysql_close($conn);
?>
</table>
View.php:
<?php
require("db.php");
$id =$_REQUEST['BookID'];
$result = mysql_query("SELECT * FROM books WHERE BookID = '$id'");
$test = mysql_fetch_array($result);
if (!$result)
{
die("Error: Data not found..");
}
$Title=$test['Title'] ;
$Author= $test['Author'] ;
$PublisherName=$test['PublisherName'] ;
$CopyrightYear=$test['CopyrightYear'] ;
if(isset($_POST['save']))
{
$title_save = $_POST['title'];
$author_save = $_POST['author'];
$name_save = $_POST['name'];
$copy_save = $_POST['copy'];
mysql_query("UPDATE books SET Title ='$title_save', Author ='$author_save',
PublisherName ='$name_save',CopyrightYear ='$copy_save' WHERE BookID = '$id'")
or die(mysql_error());
echo "Saved!";
header("Location: index.php");
}
mysql_close($conn);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
</head>
<body>
<form method="post">
<table>
<tr>
<td>Title:</td>
<td><input type="text" name="title" value="<?php echo $Title ?>"/></td>
</tr>
<tr>
<td>Author</td>
<td><input type="text" name="author" value="<?php echo $Author ?>"/></td>
</tr>
<tr>
<td>Publisher Name</td>
<td><input type="text" name="name" value="<?php echo $PublisherName ?>"/></td>
</tr>
<tr>
<td>Copyright Year</td>
<td><input type="text" name="copy" value="<?php echo $CopyrightYear ?>"/></td>
</tr>
<tr>
<td> </td>
<td><input type="submit" name="save" value="save" /></td>
</tr>
</table>
</body>
</html>
del.php：
<?php
include("db.php");
$id =$_REQUEST['BookID'];
// sending query
mysql_query("DELETE FROM books WHERE BookID = '$id'")
or die(mysql_error());
header("Location: index.php");
?>
请提供一些想法或编纂。这是我第一次使用这个概念。??
答案 0 :(得分：4)
使用主动无效逻辑..
您必须按照以下步骤操作： -
- 您必须创建一些标记状态，其中包含active和的枚举值 去活。
- 从数据库中获取数据时，您必须提供条件以仅获取活动记录。
- 如果您有活动或非活动按钮，则必须更新您的记录 基于此。
如果您将按照这些步骤进行操作!!
答案 1 :(得分：1)
enum用于boolean类型并不是一个好主意，因为它会占用更多内存。您可以在记录数据库中添加active标记。由于您已经拥有每行的唯一ID，因此您可以这样做：
SELECT * FROM `books`;
+----+-----------------------+----------------------+----------------+------+--------+
| id | title | pub | author | copy | active |
+----+-----------------------+----------------------+----------------+------+--------+
| 1 | A Matter of Time | Outskirts Press | Michael Bowler | 2010 | 0 |
| 2 | The Promise of Change | Soul Mate Publishing | Rebecca Heflin | 2011 | 0 |
+----+-----------------------+----------------------+----------------+------+--------+
对于active，您可以设置0隐藏或1显示！ ：）
A Matter of Time。它的ID为1。UPDATE `books` SET `active` = '1' WHERE `books`.`id` = 1;
+----+-----------------------+----------------------+----------------+------+--------+
| id | title | pub | author | copy | active |
+----+-----------------------+----------------------+----------------+------+--------+
| 1 | A Matter of Time | Outskirts Press | Michael Bowler | 2010 | 1 |
| 2 | The Promise of Change | Soul Mate Publishing | Rebecca Heflin | 2011 | 0 |
+----+-----------------------+----------------------+----------------+------+--------+
SELECT * FROM `books` WHERE `active` = 1;
+----+-----------------------+----------------------+----------------+------+--------+
| id | title | pub | author | copy | active |
+----+-----------------------+----------------------+----------------+------+--------+
| 1 | A Matter of Time | Outskirts Press | Michael Bowler | 2010 | 1 |
+----+-----------------------+----------------------+----------------+------+--------+
UPDATE `books` SET `active` = '0' WHERE `books`.`id` = 1;
<?php
$result = mysql_query("SELECT * FROM `books` WHERE `active` = 1");
while (false !== ($data = mysql_fetch_array($result)))
echo $data["title"];
?>
根据您的需要设置代码格式。 ：）
答案 2 :(得分：0)
插入或更新数据时，只需添加存储数据或记录状态的状态字段。
当您在查询用户中显示SELECT * FROM books where status='active'等条件时。
这对你来说很有用。
答案 3 :(得分：0)
此活动并停用帐户。在数据库表中创建一个状态列，给出类型int，如果你插入一个数据库，它会自动取0，当select table给出条件，其中status =“1”1表示有效，0表示无效。 例如：select * from login where status ='1'; Demo