我正在编写一个程序来监视计算机的各种资源,例如CPU使用情况等。我想监控GPU使用率(GPU负载,而不是温度)。
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Diagnostics;
using DannyGeneral;
namespace CpuUsage
{
public partial class Form1 : Form
{
private bool processEnded;
private Process[] processList;
private string timeStarted;
private string timeEnded;
private List<float> processValues;
private bool alreadyRun;
private DateTime dt;
private DateTime dt1;
private PerformanceCounter theCPUCounter;
private PerformanceCounter theMemCounter;
private PerformanceCounter specProcessCPUCounter;
private float cpuUsage;
private float memUsage;
private List<float> Values;
public Form1()
{
InitializeComponent();
processEnded = false;
processList = Process.GetProcesses();
for (int i = 0; i < processList.Count(); i++)
{
listView1.Items.Add(processList[i].ProcessName);
}
processValues = new List<float>();
alreadyRun = false;
dt = DateTime.Now;
Values = new List<float>();
theCPUCounter = new PerformanceCounter("Processor", "% Processor Time", "_Total");
theMemCounter = new PerformanceCounter("Memory", "Available MBytes");
specProcessCPUCounter = new PerformanceCounter("Process", "% Processor Time", Process.GetCurrentProcess().ProcessName);
Logger.Write("The Program Started At *** " + DateTime.Now.ToShortTimeString());
}
private void Form1_Load(object sender, EventArgs e)
{
}
private void timer1_Tick(object sender, EventArgs e)
{
memUsage = theMemCounter.NextValue();
label1.Text = memUsage.ToString();
Logger.Write("Memory Usage " + memUsage.ToString());
cpuUsage = this.theCPUCounter.NextValue();
label2.Text = cpuUsage.ToString();
Logger.Write("Cpu Usage " + this.cpuUsage.ToString());
Values.Add(cpuUsage);
isProcessRunning();
if (alreadyRun == true)
{
processValues.Add(cpuUsage);
}
}
答案 0 :(得分:3)
video card's own CPU
称为GPU
。
在video
菜单的搜索框中查找与其相关的效果计数器或Start->Run->PerfMon
(使用PerfMon
或输入Start
;右键单击图表并选择{ {1}})。
如果您的视频卡制造商没有为GPU提供任何性能计数器,那么您无法获得。