我正在尝试创建一个包含用户名和用户ID的微调器。我只想显示用户名而不是userID。但是当选择用户时,我想知道该用户的userID是什么。我使用唯一标识符ID作为用户ID。
非常感谢帮助,谢谢。
编辑:解决了!我只是保留一个ID为与spinner 顺序相同的数组答案 0 :(得分:2)
您可以为您的微调器创建自定义适配器:
public class CustomSpinnerAdapter : BaseAdapter
{
readonly Activity _context;
private List<Users> _items;
public ComboBoxAdapter(Activity context, List<Users> listOfItems)
{
_context = context;
_items = listOfItems;
}
public override int Count
{
get { return _items.Count; }
}
public override Java.Lang.Object GetItem(int position)
{
return position;
}
public override long GetItemId(int position)
{
return position;
}
public override View GetView(int position, View convertView, ViewGroup parent)
{
var item = _items[position];
var view = (convertView ?? context.LayoutInflater.Inflate(Android.Resource.Layout.SimpleSpinnerDropDownItem,
parent,
false));
var name = view.FindViewById<TextView>(Android.Resource.Id.Text1);
name.Text = item.Name;
return view;
}
public Users GetItemAtPosition(int position)
{
return _items[position];
}
}
此外,您还需要创建包含用户信息的类:
public class Users
{
int Id{get;set;}
string Name{get;set;}
}
然后,您可以使用数据创建和填充微调器:
[Activity(Label = "Spinner Activity")]
public class SpinnerActivity : Activity
{
private List<Users> _users;
protected override void OnCreate(Bundle bundle)
{
base.OnCreate(bundle);
SetContentView(Resource.Layout.LayoutWithSpinner);
var spinner = FindViewById<Spinner>(Resource.Id.spinner);
//you need to add data to _users before creating adapter
var adapter = new CustomSpinnerAdapter(this,_users);
spinner.Adapter = adapter;
spinner.ItemSelected += SpinnerItemSelected;
}
private void SpinnerItemSelected(object sender, AdapterView.ItemSelectedEventArgs e)
{
Toast.MakeText(this, "Id:"+_users[e.Position].Id +" Name"+_users[e.Position].Name, ToastLength.Long).Show();
}
}