以下是我在SSIS脚本任务中使用的代码。我试图使两个插入原子,因为他们处理类似的客户。
第一个.executeNonQuery()
工作正常,按原样锁定SQL表。
第二个.executNonQuery()
会抛出错误:
ExecuteNonQuery需要命令才能拥有事务 分配给该命令的连接位于挂起的本地事务中。 该命令的Transaction属性尚未初始化。
代码:
ConnectionManager cm;
SqlTransaction sqlTrans;
SqlConnection sqlConn;
SqlCommand sqlComm;
cm = Dts.Connections["connectionManager"];
try
{
//Set 'global' variables
SqlParameter agentID = new SqlParameter("@agentID", 1000018); //retrievedMessage.Substring(2, 10));//Primary key
SqlParameter lastChangeOperator = new SqlParameter("@lastChangeOperator", "LVO");
SqlParameter lastChangeDate = new SqlParameter("@lastChangeDate", DateTime.Now);
SqlParameter controlId = new SqlParameter("@controlID", 1); //Hard-coded value for testing - CHANGE LATER
//Set variables for Agent table
SqlParameter entityType = new SqlParameter("@entityType", "P");//retrievedMessage.Substring(162, 1));
SqlParameter fName = new SqlParameter("@fName", "test");//retrievedMessage.Substring(12, 25));
SqlParameter lName = new SqlParameter("@lName", "test");//retrievedMessage.Substring(37, 35));
SqlParameter suffix = new SqlParameter("@suffix", "test");//retrievedMessage.Substring(72, 10));
SqlParameter corporateName = new SqlParameter("@corporateName", "Initech");//retrievedMessage.Substring(82, 80));
//Insert record into Agent table
sqlConn = (SqlConnection)cm.AcquireConnection(Dts.Transaction);
sqlComm = new SqlCommand
(
"SET IDENTITY_INSERT Agent ON " +
"INSERT INTO Agent (UniqueAgentId, EntityType, FirstName, LastName, NameSuffix, CorporateName, LastChangeOperator, LastChangeDate, ControlId) " +
"VALUES (@agentID, @entityType, @fName, @lName, @suffix, @corporateName, @lastChangeOperator, @lastChangeDate, @controlID)" +
"SET IDENTITY_INSERT Agent OFF",
sqlConn//, sqlTrans
);
sqlTrans = sqlConn.BeginTransaction("SqlAgentTableUpdates");
sqlComm.Parameters.Add(agentID);
sqlComm.Parameters.Add(lastChangeOperator);
sqlComm.Parameters.Add(lastChangeDate);
sqlComm.Parameters.Add(controlId);
sqlComm.Parameters.Add(entityType);
sqlComm.Parameters.Add(fName);
sqlComm.Parameters.Add(lName);
sqlComm.Parameters.Add(suffix);
sqlComm.Parameters.Add(corporateName);
sqlComm.Transaction = sqlTrans;
sqlComm.ExecuteNonQuery();
//Set variables for AgentIdentification table
SqlParameter taxIdType = new SqlParameter("taxIdType", "S");//Hard-coded value for testing - CHANGE LATER
SqlParameter agentTaxId = new SqlParameter("@agentTaxId", "999999999");//Hard-coded value for testing - CHANGE LATER
//Insert record into AgentIdentification table
sqlConn = (SqlConnection)cm.AcquireConnection(Dts.Transaction);
sqlComm = new SqlCommand
(
"INSERT INTO AgentIdentification (UniqueAgentId, TaxIdType, AgentTaxId, LastChangeOperator, LastChangeDate, ControlId) " +
"VALUES (@agentID, @taxIdType, @agentTaxId, @lastChangeOperator, @lastChangeDate, @controlId)",
sqlConn//, sqlTrans
);
sqlComm.Parameters.Add(taxIdType);
sqlComm.Parameters.Add(agentTaxId);
sqlComm.Transaction = sqlTrans;
sqlComm.ExecuteNonQuery();
}
catch (Exception)
{
sqlTrans.Rollback();
cm.ReleaseConnection(sqlConn);
}
finally
{
sqlTrans.Commit();
cm.ReleaseConnection(sqlConn);
}
修改
我能够通过消除第二个连接来使这个事务工作。但是,两个查询都使用几个相同的变量(SqlParameters)。我被迫复制这些,以便运行没有错误。有没有办法让他们分享变量,所以我不必浪费空间重新创建它们?
答案 0 :(得分:0)
事务不能跨越多个连接... cm.AcquireConnection
每次都返回一个新连接吗?如果是这样,请尝试对两个命令使用相同的连接。
答案 1 :(得分:0)
使用transactionscope
using(TransactionScope ts = new TransactionScope())
{
using(SqlConnection conn = new SqlConnection(myconnstring)
{
conn.Open();
//call first executenonquery
//call second executenonquery
ts.Complete();
conn.Close();
}
}
答案 2 :(得分:0)
我认为问题可能出在连接上,或者当您将命令设置为第二个插入的新命令时,您可以使用具有相同连接的两个不同命令,或者只使用一个命令来更改CommandText属性。
希望这有助于...... Using SqlTransaction