我不清楚为什么我的脚本的子类别“论坛”没有被浏览到相应的类别。相反,子类别强制脚本重复类别代码。
如下图所示,有一个类别Test,该类别包括Test和Bugs。然而,Bugs滑入第二个表,它不应该是两个测试类别都是一个,而是看起来像数据库中有两个类别叫做Test。我的代码中有什么错误,Bugs被推入拷贝类别“测试”而不是正确的测试 - 只是一个简单的测试论坛?
这是代码。
<?php
include 'connect.php';
include 'header.php';
$sql = "SELECT
categories.cat_id,
categories.cat_name,
forums.forum_id,
forums.forum_cat,
forums.forum_name,
forums.forum_desc,
COUNT(forums.forum_id) AS forums
FROM
categories
LEFT JOIN
forums
ON
forums.forum_cat = categories.cat_id
GROUP BY
forums.forum_name, forums.forum_desc, forums.forum_id
ORDER BY
categories.cat_id ASC
";
$result = mysql_query($sql);
if(!$result)
{
echo 'The categories could not be displayed, please try again later.';
}
else
{
if(mysql_num_rows($result) == 0)
{
echo 'No categories defined yet.';
}
else
{
//prepare the table
while($row = mysql_fetch_assoc($result))
{
echo '<table border="1">
<tr>
<th>' . $row['cat_name'] . '</th><th></th>
</tr>';
echo '<tr>';
echo '<td class="leftpart">';
echo '<h3><a href="viewforum.php?id=' . $row['forum_id'] . '">' . $row['forum_name'] . '</a></h3>' . $row['forum_desc'];
echo '</td>';
echo '<td class="rightpart">';
//fetch last topic for each cat
$topicsql = "SELECT
topic_id,
topic_subject,
topic_date,
topic_cat
FROM
topics
WHERE
topic_cat = " . $row['forum_id'] . "
ORDER BY
topic_date
DESC
LIMIT
1";
$topicsresult = mysql_query($topicsql);
if(!$topicsresult)
{
echo 'Last topic could not be displayed.';
}
else
{
if(mysql_num_rows($topicsresult) == 0)
{
echo 'no topics';
}
else
{
while($topicrow = mysql_fetch_array($topicsresult))
echo '<a href="viewtopic.php?id=' . $topicrow['topic_id'] . '">' . $topicrow['topic_subject'] . '</a> at ' . date('d-m-Y', strtotime($topicrow['topic_date']));
}
}
echo '</td>';
echo '</tr>';
echo '</br>';
}
}
}
include 'footer.php';
?>
表格结构
分类
cat_id | int(8) | primary | auto incr
cat_name | var(255)
|2|Damm
|3|Hmm
|1|Test
论坛
forum_id | int(8) | primary | auto_incr
forum_cat | int(8) <-- forum cat "category" is just ID of category it belongs to
forum_name | var(255)
forum_desc | var(255)
|1|1|Test|Just a simple forum test
|2|3|Lol
|3|1|Bugs|Bugs and related go here
主题
topic_id | int(8) | primary | auto_incr
topic_subject | var(255)
topic_date | datetime
topic_cat | int(8)
topic_by | int(8)
|1|Test|2012-07-31 23:12:47|1|1
我个人尝试了不同的事情,但仍然无法弄清楚为什么会这样。
答案 0 :(得分:1)
您将获得
的结果cat_id 1, forum_id 1
cat_id 1, forum_id 2
cat_id 1, forum_id 3
cat_id 2, forum_id 4
但是你在一个循环中输出所有内容,所以你需要做的是记住显示的最后一个标题,如果你在一个新的类别中,只显示一个新标题。
以下是一个例子,并不完美,但会给你一个开始
// Start the table here - outside the loop
echo '<table border="1">
// Here's how you track if you need the header
$lastCatID = -1
// Now loop
while($row = mysql_fetch_assoc($result))
{
// Only show cat header on condition
if ($lastCatID <> $row['cat_id']) {
echo '
<tr>
<th>' . $row['cat_name'] . '</th><th></th>
</tr>';
// Note that you've shows this header so you don't show it again.
$lastCatID = $row['cat_id'];
}
// Now output the rest
echo '<tr>';
echo '<td class="leftpart">';
etc....
echo '</tr>';
}
// Now close the table now you're all done looping.
echo '</table>';
希望有所帮助。你应该能够从那里扩展以适应你的风格。