您好我有以下4D矩阵
for idx_number_panels = 1:length(number_panels) % range of PV panel units examined
for number_turbines = 0:2 % range of wind turbine units examined
for number_batteries = 1:10 % range of battery units examined
for h=2:25 %# hours
for d = 1:number_of_days %# which day
n = h + 24*(d-1);
% hourly_deficit_1(...,..., h, d)= Demand(n)-(PV_supply(n)... %
hourly_total_RES(idx_number_panels,number_turbines + 1,number_batteries, h,d)
我想从上面的4D矩阵中每24行删除整行,从而调整矩阵的大小。这是可能的,如何做到这一点,因为文档似乎没有帮助
谢谢
答案 0 :(得分:0)
仅将那些行的hourly_total_RES编入索引并分配回hourly_total_RES。
trashidx = 1:24:idx_number_panels;
keepidx = setdiff(1:idx_number_panels,trashidx);
hourly_total_RES = hourly_total_RES(keepidx,:,:,:);
而且我不知道为什么以上不是格式化代码....