如何在前一个值相同时将列值空白

Question

作为小组发现的结果，我得到类似

的内容

id   name                               date            project
2898 Noemi Araceli Farre Gutierrez      2012-07-23      mr12249-Northgate Field  
2898 Noemi Araceli Farre Gutierrez      2012-07-24      mr12251-Marketon Field  
2898 Noemi Araceli Farre Gutierrez      2012-07-25      mr12251-Marketon Field  
2898 Noemi Araceli Farre Gutierrez      2012-07-26      mr12249-Northgate Field 
3047 Mauricio Javier García             2012-07-22      mr12249-Northgate Field  
3047 Mauricio Javier García             2012-07-23      mr12251-Marketon Field  
3047 Mauricio Javier García             2012-07-26      mr12251-Marketon Field 

在我看来，我需要避免重复id和名称，并显示如下：

id   name                               date            project
2898 Noemi Araceli Farre Gutierrez      2012-07-23      mr12249-Northgate Field  
                                        2012-07-24      mr12251-Marketon Field  
                                        2012-07-25      mr12251-Marketon Field  
                                        2012-07-26      mr12249-Northgate Field 
3047 Mauricio Javier García             2012-07-22      mr12249-Northgate Field  
                                        2012-07-23      mr12251-Marketon Field  
                                        2012-07-26      mr12251-Marketon Field 

我可以通过比较视图中foreach循环期间的当前值和之前的值来做到这一点，但在我看来，必须有一个更好的，蛋糕方式。

Answer 1

对此没有“更好的蛋糕方式”。这是一个简单的PHP逻辑。

$currentName = null;
foreach ($results as $row) {
    if ($row['name'] != $currentName) {
        $currentName = $row['name'];
        echo $currentName;
    }
    else {
        // Do not display anything
        // you may need to echo some tab characters or something to keep
        // the table formatted
    }
}