Question

我有以下codeigniter模型函数：

function get_successful($project_id, $amount_backed){
    $data = '';

    $this->db->where('id', $project_id); 
    $this->db->where($amount_backed >= 'funding_goal'); //HELP HERE
    $this->db->where('published', '1'); 

......

    return $data;
}

我只需要获取变量$amount_backed高于或等于字段'funding_goal'的记录。

如何使用codeigniters活动记录来完成这项工作？

Answer 1

一种可能性是：

$this->db->where('funding_goal <=', $amount_backed);

另请参阅CodeIgniter User Guide，搜索$this->db->where();并查看Custom key/value method，有以下示例：

$ this-＆gt; db-＆gt; where（'id＆lt;'，$ id）;

P.s。：还有两种选择：关联数组方法和自定义字符串。

Answer 2

你可以使用： $this->db->where("funding_goal < $amount_backed")

a < b == b>=a

function get_successful($project_id, $amount_backed){
    $data = '';

    $this->db->where('id', $project_id); 
    $this->db->where("funding_goal < $amount_backed"); //HELP HERE
    $this->db->where('published', '1'); 

......

    return $data;
}

笨。如何返回变量值大于数据库中字段的记录？

2 个答案: