Question

我有一个文件名列表要通过processTestFile（）函数运行，该函数返回我想要存储的结果字典：

 # Count success or failure of test cases
  counts = {
    "success": 0,
    "failure": 0 
    }

主流程循环如下所示：

for fileName in all_files(fileReferences["testCasesPath"],"*.txt") :
    print "\n\nRunning test case file = ", fileName
    myCounts = processTestFile(fileName)

我想的是：

  myArray = {}
  myArray[fileName] = myCounts

我将引用为：

for name in myArray
    print name, myArray[name] ["success"], myArray[name] ["failure"]

我怀疑这段代码是否有用。你有什么建议吗？

Answer 1

myArray是dict的奇怪名称。确保将外部循环

初始化

myArray = {}
for fileName in all_files(fileReferences["testCasesPath"], "*.txt"):
    print "\n\nRunning test case file = ", fileName
    myCounts = processTestFile(fileName)
    myArray[fileName] = myCounts

for name, value in myArray.items()
    print name, value["success"], value["failure"]

如何在for循环中组织函数结果？

1 个答案: