我正在设计一个媒体播放器,我设计了一个电影课程。 Movie类有一个MovieInfo成员,它继承自MediaInfo。 MediaInfo有几个属性表示Movie文件的元数据(就是你所说的?),例如文件长度,文件大小,文件路径等。为了提取这些信息,我使用Shell32。
问题是Shell32中提供的方法非常非常慢。在我的数据库中有1部电影,这不是问题,但有10部电影,它开始变得明显,有100部电影,程序加载大约需要5分钟,而且有一些情况我必须重新初始化运行期间的电影,它再次停止程序的流程。
MediaInfo构造函数调用Initialize方法:
/// <summary>
/// Initializes all the information variables of the class.
/// </summary>
private void Initialize()
{
Folder mediaFolder = Shell32Processing.GetShellFolder(this.path);
FolderItem media = Shell32Processing.GetShellFolderItem(this.path);
//initialize bit rate value
this.bitrate = mediaFolder.GetDetailsOf(media, 28);
//initialize date accessed value
this.dateAccessed = mediaFolder.GetDetailsOf(media, 5);
//initialize date created value
this.dateCreated = mediaFolder.GetDetailsOf(media, 4);
//initialize date modified value
this.dateModified = mediaFolder.GetDetailsOf(media, 3);
//initialize data rate value
this.dataRate = mediaFolder.GetDetailsOf(media, 279);
//initialize file name value
this.fileName = mediaFolder.GetDetailsOf(media, 155);
//initialize file type value
this.fileType = mediaFolder.GetDetailsOf(media, 181);
//initialize folder value
this.folder = mediaFolder.GetDetailsOf(media, 177);
//initialize folder name value
this.folderName = mediaFolder.GetDetailsOf(media, 175);
//initialize folder path value
this.folderPath = mediaFolder.GetDetailsOf(media, 176);
//initialize frame height value
this.frameHeight = mediaFolder.GetDetailsOf(media, 280);
//initialize frame rate value
this.frameRate = mediaFolder.GetDetailsOf(media, 281);
//initialize frame width value
this.frameWidth = mediaFolder.GetDetailsOf(media, 282);
//initialize length value
this.length = mediaFolder.GetDetailsOf(media, 27);
//initialize title value
this.title = FileProcessing.GetFileTitle(this.path);
//initialize total bitrate value
this.totalBitrate = mediaFolder.GetDetailsOf(media, 283);
//initialize size value
this.size = mediaFolder.GetDetailsOf(media, 1);
}
这是Shell32Processing.GetShellFolder方法:
/// <summary>
/// Gets a Shell32 Folder, initialized to the directory of the file path.
/// </summary>
/// <param name="path">A string representing the file/folder path</param>
/// <returns>The Shell32 Folder.</returns>
public static Folder GetShellFolder(string path)
{
//extract the folder subpath from the file path
//i.e extract "C:\Example" from "C:\Example\example.avi"
string directoryPath = new FileInfo(path).Directory.ToString();
return new Shell().NameSpace(directoryPath);
}
Shell32Processing.GetShellFolderItem方法:
/// <summary>
/// Gets a Shell32 FolderItem, initialized to the item specified in the file path.
/// </summary>
/// <param name="path">A string representing the file path.</param>
/// <returns>The Shell32 FolderItem.</returns>
/// <exception cref="System.ArgumentException">Thrown when the path parameter does not lead to a file.</exception>
public static FolderItem GetShellFolderItem(string path)
{
if (!FileProcessing.IsFile(path))
{
throw new ArgumentException("Path did not lead to a file", path);
}
int index = -1;
//get the index of the path item
FileInfo info = new FileInfo(path);
DirectoryInfo directoryInfo = info.Directory;
for (int i = 0; i < directoryInfo.GetFileSystemInfos().Count(); i++)
{
if (directoryInfo.GetFileSystemInfos().ElementAt(i).Name == info.Name) //we've found the item in the folder
{
index = i;
break;
}
}
return GetShellFolder(path).Items().Item(index);
}
每次调用GetDetailsOf(这是Shell32中提供的代码)需要花费大量的时间来处理 - 我使用ANTS探查器来查找它,因为起初我无法确定什么会减慢我的程序所以得多。
所以问题是:我如何优化Shell32方法,如果不能,还有其他方法吗?
答案 0 :(得分:9)
您的代码中有很多错误。您声明问题出在您提供的代码之外,但也许我们可以通过修复已损坏的内容来解决问题。
public static Folder GetShellFolder(string path)
{
//extract the folder subpath from the file path
//i.e extract "C:\Example" from "C:\Example\example.avi"
string directoryPath = new FileInfo(path).Directory.ToString();
return new Shell().NameSpace(directoryPath);
}
您出去访问文件系统只是为了获取文件路径的目录部分(new FileInfo(path).Directory
)。您无需使用System.IO.Path.GetDirectoryName(path)
每次开始处理新项目时,都会创建一个新的shell对象。我会创建一个,处理所有项目,然后释放它。所以让我们像这样改变GetShellFolder
:
public static Folder GetShellFolder(Shell shell, string path)
{
//extract the folder subpath from the file path
//i.e extract "C:\Example" from "C:\Example\example.avi"
string directoryPath = System.IO.Path.GetDirectoryName(path);
return shell.NameSpace(directoryPath);
}
将Shell
对象传递给Initialize
方法。接下来GetShellFolderItem
。这是你的代码:
public static FolderItem GetShellFolderItem(string path)
{
if (!FileProcessing.IsFile(path))
{
throw new ArgumentException("Path did not lead to a file", path);
}
int index = -1;
//get the index of the path item
FileInfo info = new FileInfo(path);
DirectoryInfo directoryInfo = info.Directory;
for (int i = 0; i < directoryInfo.GetFileSystemInfos().Count(); i++)
{
if (directoryInfo.GetFileSystemInfos().ElementAt(i).Name == info.Name) //we've found the item in the folder
{
index = i;
break;
}
}
return GetShellFolder(path).Items().Item(index);
}
第一个错误是在访问该文件之前使用“存在文件”。不要这样做。只需访问该文件,如果该文件不存在,则会发生FileNotFoundException
。您所做的只是添加已经完成的额外工作。无论你是否这样做,它仍然可能通过“文件存在测试”,但无法访问。
接下来,您将解析目录以获取文件夹中文件的索引。这是一个严重的竞争条件。您完全可以在此处获取错误的索引值。这也没有必要,因为Folder
公开了一种方法来获取FolderItem
的名称:ParseName
。
最后,您正在创建另一个Folder
(通过调用GetShellFolder),它还会创建另一个Shell
项。您已经拥有Folder
,请使用它。
所以我们可以通过完全删除它来改变GetShellFolderItem
:
FolderItem media = mediaFolder.ParseName(System.IO.Path.GetFileName(path));
我们可以像整齐地摆脱GetShellFolder
:
private void Initialize(Shell shell)
{
Folder mediaFolder = null;
FolderItem media = null;
try
{
mediaFolder = shell.NameSpace(Path.GetDirectoryName(path));
media = mediaFolder.ParseName(Path.GetFileName(path));
...
}
finally
{
if (media != null)
Marshal.ReleaseComObject(media);
if (mediaFolder != null)
Marshal.ReleaseComObject(mediaFolder);
}
}
让我们看看所有这些差异有多大。
您也在调用GetDetailsOf,了解您已经知道或可以从媒体对象获取的内容:
//initialize folder name value
this.folderName = mediaFolder.GetDetailsOf(media, 175);
//initialize folder path value
this.folderPath = mediaFolder.GetDetailsOf(media, 176);
//initialize size value
this.size = mediaFolder.GetDetailsOf(media, 1);
将这些更改为:
//initialize folder path value
this.folderPath = Path.GetDirectoryName(path);
//initialize folder name value
this.folderName = Path.GetFileName(folderPath);
//initialize size value
this.size = media.Size;
答案 1 :(得分:0)
检查Link。基于Win-OS版本,您将获得更多关于GetDetailsOf()及其文件属性的清关。
List<string> arrHeaders = new List<string>();
Shell shell = new ShellClass();
Folder rFolder = shell.NameSpace(_rootPath);
FolderItem rFiles = rFolder.ParseName(filename);
for (int i = 0; i < short.MaxValue; i++)
{
string value = rFolder.GetDetailsOf(rFiles, i).Trim();
arrHeaders.Add(value);
}
希望这对某些人有帮助。