Flex：中心窗口？

Question

我试图将一个已启动的窗口置于flex中，有一个NativeWindow.x和NativeWindow.y但是flex使用没有这些属性的Window类，所以有人知道如何使窗口居中吗？谢谢！

Answer 1

我明白了：

window.nativeWindow.x = (Screen.mainScreen.bounds.width - window.width)/2;
window.nativeWindow.y = (Screen.mainScreen.bounds.height - window.height)/2;

我认为你必须把这个AFTER window.open（）称为。

Answer 2

这就是我使用的

nativeWindow.x = (Capabilities.screenResolutionX - nativeWindow.width) / 2; nativeWindow.y = (Capabilities.screenResolutionY - nativeWindow.height) / 2;

似乎运作良好

Answer 3

这不是更好吗？

示例文档：

// center the window on the screen
var screenBounds:Rectangle = Screen.mainScreen.bounds;
nativeWindow.x = (screenBounds.width - nativeWindow.width) / 2;
nativeWindow.y = (screenBounds.height - nativeWindow.height) / 2;

from livedocs: about window containers ¨

即使在多屏幕系统（Win7）上，这两种解决方案也适用于我

Answer 4

实际上这在flex 4.5及以上版本中效果更好

nativeWindow.x = (Screen.mainScreen.bounds.width - nativeWindow.width)/2;
nativeWindow.y = (Screen.mainScreen.bounds.height - nativeWindow.height)/2;