唯一保证永远存在的是messagesByDate obj。 名为“15 MAY 2012”的数组和对象由服务器（无控制）生成，基于此日期是否存在消息。
如果您注意到表示的第一个日期是数组，而其他日期是包含已编号的其他对象的对象。
问题1：如何在不知道将出现什么日期的情况下解析这个问题？
问题2：某些消息是在数组中而不是在对象中。我如何将它们放在一个ArrayList中。而是在数组中，因为数组不会一直存在。
请帮助我，因为我最后一件头发
感谢。
{
"messagesByDate":{
"15 May 2012":[
{
"id":"1383483367",
"conversation_id":"274618561",
"user_id":"4318264",
"message":"ok will do",
"date_sent":"1337133515",
"date_sent_ago":"7 mins ago"
},
{
"id":"1380222533",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"ok well hmu",
"date_sent":"1337085122",
"date_sent_ago":"13 hrs ago"
},
{
"id":"1380172978",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"superhead",
"date_sent":"1337083910",
"date_sent_ago":"13 hrs ago"
},
{
"id":"1380130860",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"you ready B",
"date_sent":"1337082797",
"date_sent_ago":"14 hrs ago"
},
{
"id":"1378841432",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"hit my cell tho",
"date_sent":"1337054524",
"date_sent_ago":"22 hrs ago"
},
{
"id":"1378836763",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"whats up baby",
"date_sent":"1337054475",
"date_sent_ago":"22 hrs ago"
}
],
"12 May 2012":{
"6":{
"id":"1362948558",
"conversation_id":"274618561",
"user_id":"4318264",
"message":"ok ima text u",
"date_sent":"1336819668",
"date_sent_ago":"3 days ago"
}
},
"11 May 2012":{
"7":{
"id":"1361356267",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"yea thats cool",
"date_sent":"1336790738",
"date_sent_ago":"3 days ago"
},
"8":{
"id":"1357783913",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"sorry im here. would u like to exchange numebers instead?",
"date_sent":"1336722533",
"date_sent_ago":"4 days ago"
},
"9":{
"id":"1357759262",
"conversation_id":"274618561",
"user_id":"5159567",
"message":"hello?",
"date_sent":"1336721851",
"date_sent_ago":"4 days ago"
}
}
}
}
答案SORTA-KINDA
JSONObject dateHolder = r.getJSONObject("messagesByDate");
Iterator holderItr = dateHolder.keys();
while(holderItr.hasNext()){
String thisdate = holderItr.next().toString();
Object date = dateHolder.get(thisdate);
if (date instanceof JSONArray) {
System.out.println(thisdate+" is an ARRAY.");
JSONArray jarray = (JSONArray) date;
for(int x=0;x<jarray.length();x++){
String msgId = jarray.getJSONObject(x).getString("id");
String msgConvoId = jarray.getJSONObject(x).getString("conversation_id");
String msgUserId = jarray.getJSONObject(x).getString("user_id");
String msgBody = jarray.getJSONObject(x).getString("message");
String msgDateSent = jarray.getJSONObject(x).getString("date_sent");
String msgDateSentAgo = jarray.getJSONObject(x).getString("date_sent_ago");
HashMap<String,String> temp = new HashMap<String,String>();
temp.put("msgId",msgId);
temp.put("msgUserId", msgUserId);
temp.put("msgBody", msgBody);
temp.put("msgDateSent", msgDateSent);
temp.put("msgDateSentAgo", msgDateSentAgo);
messages.add(temp);
}
} else {
System.out.println(thisdate+" is an OBJECT.");
JSONObject jobj = (JSONObject) date;
Iterator insideDate = jobj.keys();
while(insideDate.hasNext()){
String number = insideDate.next().toString();
System.out.println(number);
String msgId = jobj.getJSONObject(number).getString("id");
String msgConvoId = jobj.getJSONObject(number).getString("conversation_id");
String msgUserId =jobj.getJSONObject(number).getString("user_id");
String msgBody = jobj.getJSONObject(number).getString("message");
String msgDateSent = jobj.getJSONObject(number).getString("date_sent");
String msgDateSentAgo = jobj.getJSONObject(number).getString("date_sent_ago");
HashMap<String,String> temp = new HashMap<String,String>();
temp.put("msgId",msgId);
temp.put("msgUserId", msgUserId);
temp.put("msgBody", msgBody);
temp.put("msgDateSent", msgDateSent);
temp.put("msgDateSentAgo", msgDateSentAgo);
messages.add(temp);
}
}
}
这给了我HashMap中的所有消息，并将它添加到一个名为messages的ArrayList，就像我想要的那样，但它按日期排序。 json按日期列出...任何人都知道是否有办法指导json阅读？或者我的WHILE和FOR循环乱序？我可以用密钥对哈希图进行排序吗？我会谷歌...
答案 0 :(得分：1)
首先创建一个这样的类：
import java.util.LinkedList;
import android.util.Log;
public class Message{
private LinkedList<String> id = new LinkedList<String>();
private LinkedList<String> conversation_id = new LinkedList<String>();
private LinkedList<String> user_id = new LinkedList<String>();
private LinkedList<String> message = new LinkedList<String>();
private LinkedList<String> date_sent = new LinkedList<String>();
private LinkedList<String> date_sent_ago = new LinkedList<String>();
public LinkedList<String> getId() {
return id;
}
public void setId(String id) {
this.id.add(id);
}
.
.
.
// For checking response after you get info from server
public void printContent() {
for(String str : id)
Log.i("Id>>>", str);
.
.
.
}
}
然后你需要在onCreate（）中调用server添加这段代码：
if(Manager.isOnline(this)) // Check Internet connection and if you find it then
new MyAsyncTask().execute();
现在，您应该添加此类：
public class MyAsyncTask extends AsyncTask<Void, Void, Boolean> {
@Override
protected void onPreExecute() {
Log.i(TAG, "MyAsyncTask is about to start...");
showProgressBar();
}
@Override
protected Boolean doInBackground(Void... params) {
boolean status = false;
// Get News items in json format
msg = getMessageItems(); // msg is an instance of Message class define it as global variable.
msg.printContent(); // Check result in logcat
if(msg != null)
status = true;
return status;
}
@Override
protected void onPostExecute(Boolean result) {
Log.i(TAG, "MyAsyncTask finished its task. Data returned to caller.");
if(result)
displayData();
hideProgressBar();
}
}
这里我们将连接到服务器，获取Json数据并解析它。
private Menu getMenuItems() {
Message mMessage = new Message ();
String response = null;
String connection = **YOUR_URL**;
try {
URL url = new URL(connection);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
int responseCode = conn.getResponseCode();
Log.i(TAG, "Try to open: " + connection);
Log.i(TAG, "Response code is: " + responseCode);
if (responseCode == HttpURLConnection.HTTP_OK) {
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
if (in != null) {
StringBuilder strBuilder = new StringBuilder();
// Read character by character
int ch = 0;
while ((ch = in.read()) != -1)
strBuilder.append((char) ch);
// get returned message and show it
response = strBuilder.toString();
Log.i("JSON returned by server:", response);
JSONObject jObject = new JSONObject(response);
JSONArray contestantObjects = jObject.getJSONArray("**messagesByDate**");
for(int i=0; i<contestantObjects.length(); i++){
mMessage .setId(contestantObjects.getJSONObject(i).getString("id").toString());
// Repeat this to get all of other items
}
}
in.close();
} else
Log.e(TAG, "Couldn't open connection in getMenuItems()");
} catch (IOException e) {
e.printStackTrace();
} catch (JSONException e) {
e.printStackTrace();
}
return mMessage;
}
现在你有一个对象，它的每个项目都是一个列表。您可以在显示方法中执行任何操作。您可以将其作为对象传递给适配器以显示其数据。
private void displayData() {
messageAdapter.setData(msg);
listView.setAdapter(messageAdapter);
}
希望此示例代码可以帮助您。
答案 1 :(得分：0)
JSONObject json = service.getJunk();
JSONObject msgJson = json.getJSONObject("messagesByDate");
for( Iterator it = msgJson.keys(); it.hasNext(); ) {
Object obj = msgJson.get( (String)it.next() );
if( obj instanceof JSONObject ) {
JSONObject jobj = (JSONObject)obj;
// process json object
} else {
JSONArray arry = (JSONArray)obj;
// process array
}
}