public class SaveData extends Activity implements OnClickListener {
private DataManipulator dh;
static final int DIALOG_ID = 0;
@Override
protected void onCreate(Bundle savedInstanceState){
super.onCreate(savedInstanceState);
setContentView(R.layout.addname);
View add = findViewById(R.id.Button01add);
add.setOnClickListener(this);
View home = findViewById(R.id.Button01home);
home.setOnClickListener(this);
}
public void onClick(View v){
switch(v.getId()){
case R.id.Button01home:
Intent i = new Intent(this, DatabaseSample.class);
startActivity(i);
break;
case R.id.Button01add:
View editText1 = (EditText) findViewById(R.id.name);
String myEditText1=((TextView) editText1).getText().toString();
this.dh = new DataManipulator(this);
this.dh.insert(myEditText1);
showDialog(DIALOG_ID);
break;
}
}
protected final Dialog onCreateDialog(final int id) {
Dialog dialog = null;
switch(id) {
case DIALOG_ID:
AlertDialog.Builder builder = new AlertDialog.Builder(this);
builder.setMessage("Information saved successfully ! Add Another Info?")
.setCancelable(false)
.setPositiveButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
SaveData.this.finish();
}
})
.setNegativeButton("Yes", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
});
AlertDialog alert = builder.create();
dialog = alert;
break;
default:
}
return dialog;
}
}
当我点击模拟器上的保存数据时,我无法将数据保存到数据库中 java.lang.IllegalArgumentException:无法将此sql的bindargs传递给newtable(name)值(?)
public class DataManipulator {
private static final String DATABASE_NAME = "mydatabase.db";
private static final int DATABASE_VERSION = 1;
static final String TABLE_NAME = "newtable";
private static Context context;
static SQLiteDatabase db;
private SQLiteStatement insertStmt;
private static final String INSERT = " into " + TABLE_NAME + " (name) values (?)";
public DataManipulator(Context context) {
DataManipulator.context = context;
OpenHelper openHelper = new OpenHelper(DataManipulator.context);
DataManipulator.db = openHelper.getWritableDatabase();
this.insertStmt = DataManipulator.db.compileStatement(INSERT);
}
public long insert(String name) {
this.insertStmt.bindString(1, name);
return this.insertStmt.executeInsert();
}
public void deleteAll() {
db.delete(TABLE_NAME, null, null);
}
public List<String[]> selectAll()
{
List<String[]> list = new ArrayList<String[]>();
Cursor cursor = db.query(TABLE_NAME, new String[] { "name"}, null, null, null, null, null);
int x=0;
if (cursor.moveToFirst()) {
do {
String[] b1=new String[]{cursor.getString(0)};
list.add(b1);
x=x+1;
} while (cursor.moveToNext());
}
if (cursor != null && !cursor.isClosed()) {
cursor.close();
}
cursor.close();
return list;
}
public void delete(int rowId) {
db.delete(TABLE_NAME, null, null);
}
private static class OpenHelper extends SQLiteOpenHelper {
OpenHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}
@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL("CREATE TABLE " + TABLE_NAME + " (name TEXT)");
}
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
onCreate(db);
}
}
}
任何人都可以帮助我
答案 0 :(得分:2)
更改;
public long insert(String name) {
this.insertStmt.bindString(1, name);
return this.insertStmt.executeInsert();
}
要:
public long insert(String name) {
ContentValues args = new ContentValues();
args.put("name", name);
return db.insert(TABLE_NAME, null, args);
}
答案 1 :(得分:0)
您的插入语句需要阅读:
private static final String INSERT = "INSERT into " + TABLE_NAME + " (name) values (?)";
编辑: Waqas发布的方式是在Android中使用SQLite的更好方法。用他说的话。