Question

我有以下字符串作为HTTPResponse。它采用JSON格式。

  [
    {
       "From":"en",
       "OriginalTextSentenceLengths":[
          5
       ],
       "TranslatedText":"Hallo",
       "TranslatedTextSentenceLengths":[
          5
       ]
    },
    {
       "From":"en",
       "OriginalTextSentenceLengths":[
          8
       ],
       "TranslatedText":"Frage",
       "TranslatedTextSentenceLengths":[
          5
       ]
   },
   {
       "From":"en",
       "OriginalTextSentenceLengths":[
          6
       ],
       "TranslatedText":"Antwort",
       "TranslatedTextSentenceLengths":[
          7
       ]
  }
]

所以我正在解析这个字符串，以获得“Translated Texts array”

  String resp = "[{\"From\":\"en\",\"OriginalTextSentenceLengths\":[5],\"TranslatedText\":\"Hallo\",\"TranslatedTextSentenceLengths\":[5]},{\"From\":\"en\",\"OriginalTextSentenceLengths\":[8],\"TranslatedText\":\"Frage\",\"TranslatedTextSentenceLengths\":[5]},{\"From\":\"en\",\"OriginalTextSentenceLengths\":[6],\"TranslatedText\":\"Antwort\",\"TranslatedTextSentenceLengths\":[7]}]";

    String[] stringArray = null;
    try {
    JSONArray finalResult=null;
    JSONTokener tokener = new JSONTokener(resp); 

        finalResult = new JSONArray(tokener);
        stringArray = new String[finalResult.length()];

    for(int i=0;i<finalResult.length();i++){
        JSONObject e = finalResult.getJSONObject(i);
        Log.v("TAG",e.getString("TranslatedText"));
        stringArray[i]=e.getString("TranslatedText");
    }        

    }catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }

我从JSON对象中获取提取的“翻译文本”数组（Hallo，Frage，Antwort）......

但是当我通过直接给JSONTokener提供相同的字符串来执行相同的过程时，即在获得如下的HttpResponse后，我在finalResult = new JSONArray（tokener）行获取JSON异常.... / strong>

org.json.JSONException：
的字符0处的输入结束
String resp = getHttpResponse(uri); String[] stringArray = null; try { JSONArray finalResult=null; JSONTokener tokener = new JSONTokener(resp); finalResult = new JSONArray(tokener); stringArray = new String[finalResult.length()]; for(int i=0;i<finalResult.length();i++){ JSONObject e = finalResult.getJSONObject(i); Log.v("TAG",e.getString("TranslatedText")); stringArray[i]=e.getString("TranslatedText"); } }catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); }

我已经努力了2天来解决这个错误但是做不到..所以我在这里发帖...请帮忙

修改

我正在添加getHttpResponse的实现

public static String getHttpResponse(URI uri) { Log.d("APP_TAG", "Going to make a get request"); StringBuilder response = new StringBuilder(); try { HttpGet get = new HttpGet(); get.setURI(uri); //DefaultHttpClient httpClient = new DefaultHttpClient(); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 30000; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 30000; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); DefaultHttpClient httpClient = new DefaultHttpClient(httpParameters); Log.v("TAG","1"); HttpResponse httpResponse = httpClient.execute(get); Log.v("TAG","2"); if (httpResponse.getStatusLine().getStatusCode() == 200) { Log.d("demo", "HTTP Get succeeded"); HttpEntity messageEntity = httpResponse.getEntity(); InputStream is = messageEntity.getContent(); BufferedReader br = new BufferedReader(new InputStreamReader(is)); String line; while ((line = br.readLine()) != null) { response.append(line); } } } catch (Exception e) { Log.e("demo", e.getMessage()); } Log.d("demo", "Done with HTTP getting"); return response.toString(); }

我给getHttpResponse的uri如下

String[] texts = {"hello","question","answer"}; final String params = "appId=" + URLEncoder.encode("78280AF4DFA1CE1676AFE86340C690023A5AC139","UTF-8") + "&from=" + URLEncoder.encode("en","UTF-8") + "&to=" + URLEncoder.encode("de","UTF-8") + "&texts=" + URLEncoder.encode(buildStringArrayParam(texts),"UTF-8"); final URL url = new URL("http://api.microsofttranslator.com/V2/Ajax.svc/TranslateArray?" + params); URI myURI = java.net.URI.create(url.toString()); String resp = getHttpResponse(myURI);

这个响应字符串是我试图解析的......

这适用于buildStringArrayParam（文本）

StringBuilder targetString = new StringBuilder("[\""); String value; for(Object obj : values) { if(obj!=null) { value = obj.toString(); if(value.length()!=0) { if(targetString.length()>2) targetString.append(",\""); targetString.append(value); targetString.append("\""); } } } targetString.append("]"); return targetString.toString();

Answer 1

Ahaha ......微软。

至少在这种情况下，他们会在一开始就用（错误的？）FEFF FEFF UTF-16 byte order mark提供API响应，从而打破了大多数客户。

与the PHP guys over here already found out类似，您只需要从响应中删除前两个字节。对于代码中的例子：

JSONTokener tokener = new JSONTokener(resp.substring(2));

我担心更无害的trim()不起作用。

很难找到，因为FEFF的官方名称是“零宽度不间断空格”，所以除非你将字符串视为字符数组或注意当你的文本光标停止时它是完全不可见的使用左/右箭头键移动字符串......

请注意，您不应该对收到的任何其他HTTP响应执行此操作，这仅适用于此Microsoft API（也可能是其他人）。

Answer 2

Try GSON

尝试更改代码设计，希望它能为您提供帮助。

从网址检索内容 -

public static String getContent(String url) throws Exception {
    return(new Scanner(new URL(url).openConnection().getInputStream()).useDelimiter("/z").next());
}

玩得开心......

Answer 3

尝试使用：

HttpPost request = new HttpPost(URL);
HttpResponse response = httpClient.execute(request);

HttpEntity httpEntity = response.getEntity();
InputStream content = httpEntity.getContent();

BufferedReader reader = new BufferedReader(new InputStreamReader(content,"iso-8859-1"),8);
String resp = reader.readLine();

现在“resp”将保存可以解析的字符串...

Answer 4

After getting the HTTP Response you have to do this thing, you cant use Httpresponse directly.

HttpResponse response= null;
response = http.execute(get);
HttpEntity entity = response.getEntity();
String xmlstring = EntityUtils.toString(entity);
message = xmlstring;

JSON对象分析错误

4 个答案: