Question

我需要来自2列的TOP 1字符串，该值应按出现次数和名称递减的顺序返回。这是在SQL-Server。

这是一个示例表：

------------------------------
|   Column1    |   Column2   |
------------------------------
|     John     |   Michael   |
------------------------------
|    Thomas    |    John     |
------------------------------
|    Martin    |    Rick     |
------------------------------
|    David     |   Thomas    |
------------------------------
|     John     |   Martin    |
------------------------------

生成的订单应如下所示：

----------------------------
|   Column1    |   COUNT   |
----------------------------
|     John     |     3     |
----------------------------
|    Martin    |     2     |
----------------------------
|    Thomas    |     2     |
----------------------------
|     David    |     1     |
----------------------------
|    Michael   |     1     |
----------------------------
|     Rick     |     1     |
----------------------------

结果如何：

----------------------------
|   Column1    |   COUNT   |
----------------------------
|     John     |     3     |
----------------------------

Answer 1

select top 1 c, count(*) [Count]
from
(
   select column1 c
     from ATable
   union all
   select column2
     from ATable
) a
group by c
order by count(*) desc

获取最常用的名称并首先按字母顺序选择：

select top 1 c, count(*) [Count]
from
(
   select column1 c
     from ATable
   union all
   select column2
     from ATable
) a
group by c
order by count(*) desc, c

如果你想做同样的事情但只有一列：

select top 1 column1, count(*) [Count]
  from ATable
group by column1
order by count(*) desc, column1

Answer 2

从SQL 2005开始，您可以使用UNPIVOT：

-- Example Data
DECLARE @Data TABLE (Column1 VARCHAR(10), Column2 VARCHAR(10))
INSERT @Data VALUES ('A', 'B'), ('B', 'A'), ('C', 'A'), ('D', 'E'), ('A', 'D')

SELECT TOP 1 Name, COUNT(*)
FROM @Data d
    UNPIVOT (Name FOR Col IN (Column1, Column2)) AS unpvt
GROUP BY Name
ORDER BY COUNT(*) DESC

Answer 3

CREATE TABLE #t (Column1 nvarchar(50), Column2 nvarchar(50))
INSERT INTO #t (Column1, Column2)
VALUES ('John', 'Michael')
,('Thomas', 'John')
,('Martin', 'Rick')
,('David', 'Thomas')
,('John', 'Martin')



;WITH cte (Column1)
AS
(
    SELECT Column1
    FROM #t

    UNION ALL

    SELECT Column2
    FROM #t
)



SELECT TOP 1
        Column1
        ,COUNT(*) as [COUNT]
FROM cte
GROUP BY Column1
ORDER BY [COUNT] DESC

如何通过计数获得TOP 1出现的值，并从2列的UNION中获取名称desc

3 个答案: