Question

我尝试按照本指南操作：tutorial但是当我在网络浏览器上执行时会返回错误：

HTTP Status 404 - /
type Status report
message /
description The requested resource (/rest.api/rest/hello) is not available.

我已经在我的mac上的/ usr / local中安装了tomcat7，并在终端上使用startup.sh运行它。这是我的web.xml和Hello.java

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>HelloRest</display-name>

<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
  <param-name>com.sun.jersey.config.property.packages</param-name>
  <param-value>rest.api</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
 <servlet-name>Jersey REST Service</servlet-name>
 <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

package rest.api;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;

// POJO, no interface no extends

// The class registers its methods for the HTTP GET request using the @GET annotation. 
// Using the @Produces annotation, it defines that it can deliver several MIME types,
// text, XML and HTML. 

// The browser requests per default the HTML MIME type.

//Sets the path to base URL + /hello
@Path("/hello")
public class Hello {

// This method is called if TEXT_PLAIN is request
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
    return "Hello Jersey";
}

// This method is called if XML is request
@GET
@Produces(MediaType.TEXT_XML)
public String sayXMLHello() {
    return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}

// This method is called if HTML is request
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHtmlHello() {
    return "<html> " + "<title>" + "Hello Jersey" + "</title>"
            + "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
}

}

这是我的配置项目：

enter image description here

有什么建议吗？

Answer 1

只需在 web.xml

中使用以下配置即可

    <servlet>
        <servlet-name>ServletAdaptor</servlet-name>
        <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>ServletAdaptor</servlet-name>
        <url-pattern>/rest/*</url-pattern>
    </servlet-mapping>

希望这会对你有所帮助。

Answer 2

试试这个。

<servlet>
    <servlet-name>jersey-serlvet</servlet-name>
    <servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>com.sun.jersey.config.property.packages</param-name>
        <param-value>Your Service Package Name</param-value>
    </init-param>
    <init-param>
        <param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
        <param-value>true</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>


<servlet-mapping>
    <servlet-name>jersey-serlvet</servlet-name>
    <url-pattern>/rest/*</url-pattern>
</servlet-mapping>

访问这个：Jersey RESTful

Answer 3

在更新版本的Jersey中，servlet-class和init-param发生了变化。请尝试以下方法：

<servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
      <param-name>jersey.config.server.provider.packages</param-name>
      <param-value>Your Service Package Name</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>

这对我使用Jersey版本：2.5.1。

Answer 4

<servlet-name> jersey-serlvet </servlet-name>

<servlet-class> com.sun.jersey.spi.container.servlet.ServletContainer </servlet-class>

<init-param>

    <param-name> com.sun.jersey.config.property.packages </param-name>

    <param-value> rest.api </param-value>

</init-param>

<init-param>

    <param-name> com.sun.jersey.api.json.POJOMappingFeature </param-name>

    <param-value> true </param-value>

</init-param>

<load-on-startup>1</load-on-startup>

<servlet-name> jersey-serlvet </servlet-name>

<url-pattern> /rest/* </url-pattern>

运行Jersey项目（Rest Web服务）到tomcat

4 个答案: