我需要在服务器中使用ip-address和客户端端口。使用IOCP在C ++上编写的服务器,所以我不接受客户端,我创建新的套接字然后在这个就绪套接字上接受(AcceptEx)客户端。因为它结构sockaddr_in不正确。
我该怎么做?
谢谢!
答案 0 :(得分:5)
AcceptEx
可能会返回您的对等地址(TCP套接字的IP +端口)。
BOOL AcceptEx(
__in SOCKET sListenSocket,
__in SOCKET sAcceptSocket,
__in PVOID lpOutputBuffer,
__in DWORD dwReceiveDataLength,
__in DWORD dwLocalAddressLength,
__in DWORD dwRemoteAddressLength,
__out LPDWORD lpdwBytesReceived,
__in LPOVERLAPPED lpOverlapped
);
您应该指定lpOutputBuffer
指向具有足够大小的缓冲区以容纳2个返回的地址,然后。 dwLocalAddressLength
和dwRemoteAddressLength
应设置为缓冲区中保留的地址大小。
根据MSDN,单个地址(AcceptEx
函数)所需的缓冲区大小为sizeof(SOCKADDR_IN) + 16
:
dwLocalAddressLength [in] The number of bytes reserved for the local address information. This value must be at least 16 bytes more than the maximum address
正在使用的传输协议的长度。
当然缓冲区必须对I / O持续时间有效。您可以将其放在OVERLAPPED
结构中。像这样:
struct OverlappedAccept
:public OVERLAPPED
{
// some context information that you need
// ...
// Buffer for addresses
struct {
BYTE m_pLocal[sizeof(SOCKADDR_IN) + 16];
BYTE m_pRemote[sizeof(SOCKADDR_IN) + 16];
} m_Bufs;
};
// start accept operation
OverlappedAccept* pOver = /* ... */;
BOOL bRet = AcceptEx(
hSockListen,
hSockNew,
&pOver->m_Bufs,
0,
sizeof(pOver->m_Bufs.m_pLocal),
sizeof(pOver->m_Bufs.m_pRemote),
&dwBytes,
pOver);
I / O完成(成功)后,您可以获得地址:
sockaddr *pLocal = NULL, *pRemote = NULL;
int nLocal = 0, nRemote = 0;
GetAcceptExSockAddrs(
&pOver->m_Bufs,
0,
sizeof(pOver->m_Bufs.m_pLocal),
sizeof(pOver->m_Bufs.m_pRemote),
&pLocal,
&nLocal,
&pRemote,
&nRemote);