Question

我一直在开发系统，但是最近我无法调试为什么出现此错误不允许的方法所请求的URL不允许使用该方法。我一直在开发系统我认为问题与发布功能不允许和被某些内容打断有关，请协助我。代码：

python

#!/usr/bin/env python3
# -*- coding: utf-8 -*-

from flask import Flask, render_template, request
app = Flask(__name__)

@app.route('/')
def student():
    return render_template('index.html')

@app.route('/result',methods = ['POST', 'GET'])
def result():
    if request.method == 'POST':
        result = request.form['name']
        print(result)
        return "thank you for filling out this form"

if __name__ == '__main__':
    app.run(debug = True)
file_object = open('transferfile.txt', 'a+')
name = "Gabriel"
age = "12"
gender = "male"
file_object.write(name)
file_object.write(" ")
data = file_object.read(100)
file_object.write(age)
file_object.write(" ")
file_object.write(gender)
file_object.close()

html

<!DOCTYPE html>
<html lang="en">
<head>
    <link rel="stylesheet" href="style.css">
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>venuefast</title>
</head>
<body>
    <form class="logo" action="." method="post">fastvenue<br>
        <hr>
        <input type ="text" name="name" placeholder="name">
        <br>
        <button type="submit" value="submit">Submit</button>
    </form> 
</body>
</html>

Answer 1

由于学生函数正在index.html中呈现表单，因此只有学生函数接受POST请求才有意义：

from flask import Flask, render_template, request
app = Flask(__name__)

@app.route('/',methods = ['POST', 'GET'])
def student():
    if request.method == 'POST':
        name = request.form['name']
        return f"thank you for filling out this form {name}!"
    return render_template('index.html')


@app.route('/result')
def result():
    return 'this function does nothing yet'

if __name__ == '__main__':
    app.run(debug = True)

另一种选择，如果您打算将学生用于其他用途，则可以使结果函数呈现index.html，也可以使其接受POST请求：


from flask import Flask, render_template, request
app = Flask(__name__)

@app.route('/')
def student():
    return 'this function does nothing yet'


@app.route('/result',methods = ['POST', 'GET'])
def result():
    if request.method == 'POST':
        name = request.form['name']
        return f"thank you for filling out this form {name}!"
    return render_template('index.html')

if __name__ == '__main__':
    app.run(debug = True)

Answer 2

在HTML中尝试

<html lang="en">
<head>
    <link rel="stylesheet" href="style.css">
    <meta charset="UTF-8">
    <meta name="viewport" content="width=device-width, initial-scale=1.0">
    <title>venuefast</title>
</head>
<body>
    <form class="logo" action="/result" method="POST">
        <p>fastvenue</p>
        <br>
        <hr>
        <input type ="text" name="name" placeholder="name">
        <br>
        <button type="submit" value="submit">Submit</button>
    </form> 
</body>
</html>

405不允许使用的方法：所请求的URL不允许使用该方法

2 个答案: