Question

我要显示我的Json响应，如下所示。以下是我的课程。类名（transaction_status）不应出现在json响应中，这是他们可以以任何方式实现此建议的任何建议吗？

//Expected json response
{
    "view": {
        "payment_transaction": [
            {

                "status": "Delivered",   
                "reason": "XXX",        
                "event": [
                    {
                           "status": "Delivered",  
                           "reason": "XXX" 
                        }
                    }
                ]
            }
        ]
    }
}

// but it is coming as below 
{
    "view": {
        "payment_transaction": [
            {

                "status": "Delivered",   // 1)Coming correctly
                "reason": "XXX",         // 2)Coming correctly 
                "event": [
                    {
                        "transaction_status": { // don't want to this field to come
                            "status": "Delivered",  
                            "reason": "XXX" 
                        }
                    }
                ]
            }
        ]
    }
}

public class View {
    public static class PaymentExternalView {

     @SerializedName("status")
     private String transactionStatus;

     @SerializedName("reason")
     private String transactionStatusReason;

     private transient TransactionStatus tranStatus;

     public TransactionStatus getTranStatus() {
           return tranStatus;
     }

     public void setTranStatus(TransactionStatus tranStatus) {
           this.tranStatus = tranStatus;
     }

     public String getTransactionStatus() {  
           this.transactionStatus = tranStatus.getStatus().toString();
           return transactionStatus;
     }

     public void setTransactionStatus(String transactionStatus) {
           this.transactionStatus = transactionStatus;
     }

     public String getTransactionStatusReason() {
           this.transactionStatusReason = tranStatus.getReason().toString();
           return transactionStatusReason;
     }

     public void setTransactionStatusReason(String transactionStatusReason) {
           this.transactionStatusReason = transactionStatusReason;
     }

   }

    public static class Event {

    private TransactionStatus transactionStatus;

    //@SerializedName("status")       // If I specify these variables error is coming as Multiple json fileds 
    //private String transactionStatus;

    //@SerializedName("reason")
    //private String transactionStatusReason;


    public TransactionStatus getTransactionStatus() {
        this.transactionStatus = tranStatus.t
        return transactionStatus;
     }

     public void setTransactionStatus(TransactionStatus status) {
       this.transactionStatus = status;
     }
     /**
     public String getTransactionStatus() {
           this.transactionStatus = tranStatus.getStatus().toString();
           return transactionStatus;
     }

     public void setTransactionStatus(String transactionStatus) {
           this.transactionStatus = transactionStatus;
     }

     public String getTransactionStatusReason() {
           this.transactionStatusReason = tranStatus.getReason().toString();
           return transactionStatusReason;
     }

     public void setTransactionStatusReason(String transactionStatusReason) {
           this.transactionStatusReason = transactionStatusReason;
     }
     **/
    }
}


public class TransactionStatus {
  private String status;

  private String reason;

  public String getStatus() {
     return status;
  }
  public void setStatus(String status) {
     this.status = status;
  }
  public String getReason() {
     return reason;
  }
  public void setReason(String reason) {
     this.reason = reason;
  }
}

我无法修改我的TransactionStatus类，因为在许多其他地方都使用过该类。在事件类中，如果我尝试设置@SerializedName（“ status”）和@SerializedName（“ reason”），则会由于多个json字段而出现错误。我想显示我的状态和上一层的原因，即想摆脱json响应中的“ transaction_status”标签。

Answer 1

我猜您正在使用gson ...尝试为PaymentExternalView（包含TransactionStatus成员的类）类使用自定义序列化程序。

GsonBuilder gsonBuilder = new GsonBuilder();

JsonSerializer<PaymentExternalView> serializer = ...;  
gsonBuilder.registerTypeAdapter(PaymentExternalView.class, serializer);

Gson customGson = gsonBuilder.create();  
String customJSON = customGson.toJson(value);

然后根据需要创建json ...

JsonSerializer<PaymentExternalView> serializer = new JsonSerializer<>() {  
    @Override
    public JsonElement serialize(PaymentExternalView src, Type typeOfSrc, JsonSerializationContext context) {
        JsonObject json = new JsonObject();
        // ...
        json.addProperty("status", src.getTransactionStatus().getStatus());
        json.addProperty("reason", src.getTransactionStatus().getReason());

        return json;
    }
};

https://futurestud.io/tutorials/gson-advanced-custom-serialization-part-1

Pojo类序列化为json

1 个答案: