我有一个压缩文件夹(例如test.zip),当我将其解压缩时具有以下结构-
WebContent/config/somefiles
WebContent/css/somefile
Webcontent/fonts/somefiles
Webcontent/js/somefiles
WebContent/index.html
现在,我必须从此结构中删除WebContent。我的最终Unzip文件的根目录位置应为config
,css,js
和index.html
。
请让我知道任何有效的JAVA代码,可以先将test.zip解压缩,然后绕过WebContent文件夹,然后再次压缩WebContent中存在的所有文件。
预先感谢!
答案 0 :(得分:1)
这是一种常见的模式/活动,因此在您的工具包中应该是一个很好的模式/活动。
请参见下面的代码。有一种“选择”方法,供您根据需要自定义以驱动选择要传输或不传输的条目:
private static boolean select(String entryName) {
return true; // Customize me
}
请注意,目录可能具有目录本身的条目(例如,“ meta-inf /”)以及目录中文件的条目(例如,“ meta-inf / manifest.mf”)。跳过目录条目不会跳过目录中的条目。
还请注意,这样可以避免将其解压缩到磁盘上。应避免这种情况,因为这会增加执行时间。 (但也请注意,整个条目不会加载到内存中;内存中只有一个缓冲区充满了数据。)
假设代码在“ transfer.jar”中,用法是:
用法:sample.transfer.TransferSample inputPath outputPath
例如,在自己的jar上运行该工具:
java -classpath transfer.jar sample.transfer.TransferSample transfer.jar transfer.jar.out
Transfer from [ transfer.jar ]
Transfer to [ transfer.jar.out ]
Transfer from [ c:\dev\transfer\transfer.jar ] (absolute path)
Transfer to [ c:\dev\transfer\transfer.jar.out ] (absolute path)
Entry [ META-INF/MANIFEST.MF ]: Selected
Transferred [ 25 ] bytes
Entry [ sample/ ]: Selected
Entry [ sample/transfer/ ]: Selected
Entry [ sample/transfer/TransferSample.class ]: Selected
Transferred [ 4061 ] bytes
Entry [ sample/transfer/TransferSample.java ]: Selected
Transferred [ 3320 ] bytes
Transfer Success
代码如下:
package sample.transfer;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;
import java.util.zip.ZipOutputStream;
public class TransferSample {
public static void main(String args[]) {
if ( args.length < 2 ) {
System.out.println("Usage: " + TransferSample.class.getName() + " inputPath outputPath");
return;
}
String inputPath = args[0];
String outputPath = args[1];
System.out.println("Transfer from [ " + inputPath + " ]");
System.out.println("Transfer to [ " + outputPath + " ]");
File inputFile = new File(inputPath);
File outputFile = new File(outputPath);
System.out.println("Transfer from [ " + inputFile.getAbsolutePath() + " ] (absolute path)");
System.out.println("Transfer to [ " + outputFile.getAbsolutePath() + " ] (absolute path)");
try ( InputStream inputStream = new FileInputStream(inputFile) ) { // throws IOException
try ( OutputStream outputStream = new FileOutputStream(outputFile) ) { // throws IOException
transfer(inputStream, outputStream);
System.out.println("Transfer Success");
}
} catch ( IOException e ) {
System.err.println("Transfer Failure");
e.printStackTrace(System.err);
}
}
// All static to keep the code simpler.
public static void transfer(InputStream inputStream, OutputStream outputStream) throws IOException {
ZipInputStream zipInputStream = new ZipInputStream(inputStream);
ZipOutputStream zipOutputStream = new ZipOutputStream(outputStream);
try {
transfer(zipInputStream, zipOutputStream); // throws IOException
} finally {
zipOutputStream.finish(); // throws IOException
}
}
private static final int BUFFER_SIZE = 64 * 1024;
private static boolean select(String entryName) {
return true; // Customize me
}
public static void transfer(ZipInputStream zipInputStream, ZipOutputStream zipOutputStream) throws IOException {
byte[] buffer = new byte[BUFFER_SIZE]; // Single buffer for all transfers
ZipEntry inputEntry;
while ( (inputEntry = zipInputStream.getNextEntry()) != null ) {
String entryName = inputEntry.getName();
if ( !select(entryName) ) {
System.out.println("Entry [ " + entryName + " ]: Not selected");
continue;
} else {
System.out.println("Entry [ " + entryName + " ]: Selected");
}
zipOutputStream.putNextEntry(inputEntry); // throws IOException
if ( !inputEntry.isDirectory() ) {
long bytesTransferred = transfer(zipInputStream, zipOutputStream, buffer); // throws IOException
System.out.println("Transferred [ " + bytesTransferred + " ] bytes");
zipOutputStream.closeEntry(); // throws IOException
}
}
}
private static long transfer(InputStream inputStream, OutputStream outputStream, byte[] buffer) throws IOException {
long totalBytesRead = 0L;
int bytesRead = 0;
while ( (bytesRead = inputStream.read(buffer, 0, buffer.length)) != -1 ) { // throws IOEXception
totalBytesRead += bytesRead;
outputStream.write(buffer, 0, bytesRead);
}
return totalBytesRead;
}
}
答案 1 :(得分:0)
我相信您会想要查看java.util.zip.ZipInputStream和java.util.zip.ZipOutputStream。这些方式的工作方式是,您需要遍历所有条目,然后从输入流式传输每个条目(当然不需要的条目除外),然后将其写入输出。
要注意的事情是: