Question

这是我的JSON对象数组，其中包含嵌套对象：

var obj=   [
       {
          "ASIN":"BCXXXXX1",
          "VariationAttributes":[
             {
                "Name":"hand_orientation",
                "Value":"Left Hand"
             },
             {
                "Name":"shaft_material_type",
                "Value":"KBS Max 90 Steel"
             }
          ]
       },
       {
          "ASIN":"BCXXXXX2",
          "VariationAttributes":[
             {
                "Name":"hand_orientation",
                "Value":"Right Hand"
             },
             {
                "Name":"shaft_material_type",
                "Value":"KBS Max 90 Steel"
             }
          ]
       }
    ]

var curState=[
   {
      "Name":"hand_orientation",
      "Value":"Left Hand"
   },
   {
      "Name":"shaft_material_type",
      "Value":"KBS Max 90 Steel"
   }
]

现在，我要过滤掉具有与curState相匹配的variantAattributes的项目。

var result = obj.map(m=>m.VariationAttributes).filter(search, curState);


function search(item){
  return Object.keys(this).some((key) => item[key] === this[key]);
}

结果为空白。您可以在https://playcode.io./518049

上使用该代码

Answer 1

您可以根据回调函数使用.filter()来过滤arr。如果当前对象的VariationAttributes属性的.some()名称或值属性不等于curState对象中相应对象的属性，则回调函数将返回true，如下所示：

const arr = [{ "ASIN": "BCXXXXX1", "VariationAttributes": [{ "Name": "hand_orientation", "Value": "Left Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" } ] }, { "ASIN": "BCXXXXX2", "VariationAttributes": [{ "Name": "hand_orientation", "Value": "Right Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" } ] } ];
const curState = [{ "Name": "hand_orientation", "Value": "Left Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" } ];

const res = arr.filter(
  obj => obj.VariationAttributes.some(({Name, Value}, i) => curState[i] && (Name !== curState[i].Name || Value !== curState[i].Value))
);

console.log(res);

您还可以在JSON.stringifiy()上使用curState，以便可以将VariationAttributes的字符串版本与VariationAttributes属性的字符串版本进行比较：

const arr = [{ "ASIN": "BCXXXXX1", "VariationAttributes": [{ "Name": "hand_orientation", "Value": "Left Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" } ] }, { "ASIN": "BCXXXXX2", "VariationAttributes": [{ "Name": "hand_orientation", "Value": "Right Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" } ] } ];
const curState = [{ "Name": "hand_orientation", "Value": "Left Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" } ];

const strCurState = JSON.stringify(curState);
const res = arr.filter(
  obj => strCurState !== JSON.stringify(obj.VariationAttributes)
);

console.log(res);

Answer 2

var obj = [{ "ASIN": "BCXXXXX1", "VariationAttributes": [{ "Name": "hand_orientation", "Value": "Left Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" }] },{"ASIN":"BCXXXXX2",	"VariationAttributes": [{			"Name": "hand_orientation","Value": "Right Hand"}, {"Name": "shaft_material_type",	"Value": "KBS Max 90 Steel"}]}];
var curState = [{"Name": "hand_orientation", "Value": "Left Hand"},{"Name":"shaft_material_type", "Value": "KBS Max 90 Steel"}];

var finalResult = obj.filter(parentObj => {
    return JSON.stringify(parentObj.VariationAttributes) === JSON.stringify(curState);
});
console.log(finalResult)

变量finalResult将具有过滤后的数组。

Answer 3

看看这个。

var obj=[{ "ASIN": "BCXXXXX1", "VariationAttributes": [{ "Name": "hand_orientation", "Value": "Left Hand" }, { "Name": "shaft_material_type", "Value": "KBS Max 90 Steel" }] },{"ASIN":"BCXXXXX2",	"VariationAttributes": [{			"Name": "hand_orientation","Value": "Right Hand"}, {"Name": "shaft_material_type",	"Value": "KBS Max 90 Steel"}]}];
var curState=[{"Name": "hand_orientation", "Value": "Left Hand"},{"Name":"shaft_material_type", "Value": "KBS Max 90 Steel"}];

//var result = obj.map(m=>m.VariationAttributes).filter(search, curState);

var result = obj.filter(item => {
  return item.VariationAttributes.every(attr => {
    return curState.find(state => attr.Name === state.Name && attr.Value === state.Value);
  })
});

console.log(result);

function search(item){
  return Object.keys(this).some((key) => item[key] === this[key]);
}
//console.log(obj)

如何过滤出JSON数组中的嵌套对象？

3 个答案: