Question

因此，我在创建一个函数时会遇到麻烦，该函数将对日期及其数据进行过滤和排序，并将其放置在对象数组中。我遇到的问题是一个不同但相似的情况。原始问题来自此处：Filtering undefined from array of objects in Javascript

可以说var arrObject在一个数组中有两个以上的项目。请参阅下面的代码。我想过滤任何空字符串或未定义的值以及数组中的任何项目，然后按升序排序。按日期排序。在新数组中，我只想输出date和bus_name。请注意，数组中的名称是不同的，我想使用其他名称命名，例如以下输出：

{Date: '2012-02-11', busName: 'Thomas #2'}. ...

我该怎么做？

谢谢！

{date: " ", bus_name: 'Thomas #1', driver_name: 'Sam', time_start: '9AM', time_end: '5PM'},
{date: '2012-02-11', bus_name: 'Thomas #2', driver_name: 'Samantha', time_start: '8AM', time_end: '4PM'},
{date: '2011-02-02', bus_name: 'Thomas #3', driver_name: 'Peter', time_start: '12PM', time_end: '7PM'},
{date: '2010-06-04', bus_name: 'Thomas #4', driver_name: 'Eddie', time_start: '11AM', time_end: '6PM'},
{date: " ", bus_name: 'Thomas #5', driver_name: 'Raul', time_start: '4AM', time_end: '1PM'},
{date: '2014-04-03', bus_name: 'Thomas #6', driver_name: 'Jessie', time_start: '5AM', time_end: '2PM',
]

function fancySort(array){
   let arrayCopy = array.slice(0);
  //your sort logic can be replaced here
  arrayCopy.sort();

  return arrayCopy
}

let newArray = arrObject.filter( obj => {
  //behave same as obj.date != undefined
  return obj.date
})

let sortedDates = fancySort(newArray.map(obj => Date.parse(obj.date)));

let sortedObjArray = sortedDates.map( date=>{
  let tempObj;
  newArray.some( na=> {
    tempObj = na;
    return Date.parse(na.date) == date
  })
  return tempObj;
})

console.log(sortedObjArray);```

Answer 1

您可以过滤不需要的部分，映射具有所需属性的新对象，并按date对数组进行排序。

var array = [{ date: " ", bus_name: 'Thomas #1', driver_name: 'Sam', time_start: '9AM', time_end: '5PM' }, { date: '2012-02-11', bus_name: 'Thomas #2', driver_name: 'Samantha', time_start: '8AM', time_end: '4PM' }, { date: '2011-02-02', bus_name: 'Thomas #3', driver_name: 'Peter', time_start: '12PM', time_end: '7PM' }, { date: '2010-06-04', bus_name: 'Thomas #4', driver_name: 'Eddie', time_start: '11AM', time_end: '6PM' }, { date: " ", bus_name: 'Thomas #5', driver_name: 'Raul', time_start: '4AM', time_end: '1PM' }, { date: '2014-04-03', bus_name: 'Thomas #6', driver_name: 'Jessie', time_start: '5AM', time_end: '2PM' }],
    result = array
        .filter(o => o.date !== ' ')
        .map(({ date, bus_name }) => ({ date, bus_name }))
        .sort((a, b) => a.date.localeCompare(b.date));

console.log(result);

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从Javascript中的对象数组过滤未定义或空字符串

1 个答案: