Question

如果值与列表中的值匹配，我正在尝试从嵌套字典中提取值。

data = [
            {
                "id": 12345678,
                "list_id": 12345,
                "creator_id": 1234567,
                "entity_id": 1234567,
                "created_at": "2020-01-30T00:43:55.256-08:00",
                "entity": {
                    "id": 123456,
                    "type": 0,
                    "first_name": "John",
                    "last_name": "Doe",
                    "primary_email": "john@fakemail.com",
                    "emails": [
                        "john@fakemail.com"
                    ]
                }
            },
            {
                "id": 12345678,
                "list_id": 12345,
                "creator_id": 1234567,
                "entity_id": 1234567,
                "created_at": "2020-01-30T00:41:54.375-08:00",
                "entity": {
                    "id": 123456,
                    "type": 0,
                    "first_name": "Jane",
                    "last_name": "Doe",
                    "primary_email": "jane@fakemail.com",
                    "emails": [
                        "jane@fakemail.com"
                    ]
                }
            }
        ]

代码如下。

match_list = ['jane@fakemail.com',[]]
first_names = []
email = []
for i in match_list:
    for record in data:
        if 'primary_email' == i:
            email.append(record.get('entity',{}).get('primary_email', None))
            first_names.append(record.get('entity',{}).get('first_name', None))       
print(first_names)
print(email)

代替返回匹配值，它仅返回空列表。任何帮助，我们将不胜感激。

预期输出为

first_names = ['Jane'] and email = ['jane@fakemail.com']

Answer 1

将临时值存储在变量中，以使您的代码更易于处理：

emails = []
names = []
match_list = ['jane@fakemail.com',[]]


for item in data:
    entry = item.get('entity', {})

    fName = entry.get('first_name', '')
    pMail = entry.get('primary_email', '')

    if pMail in match_list:
        print (fName)
        print (pMail)

        emails.append(pMail)
        names.append(fName)

输出：

Jane
jane@fakemail.com

Answer 2

在代码的第六行

    if 'primary_email' == i:

您正在将match_list中的元素（即“ i”）与名为“ primary_email”的字符串而不是实际电子邮件进行比较。因为“ jane@fakemail.com”不等于“ primary_email”（字面上是字符串）。

代替

if record['entity']['primary_email'] == i:

，您的代码应该可以正常工作。

Answer 3

在您的代码中，比较'primary_email'==i时始终会得到一个空列表，该列表始终为False。

将其更改为record['entity']['primary_email']==i。

这里不需要使用get。因为如果mail与任何primary_email不匹配，则什么也不会发生。 primary_email仅在满足条件d['entity']['primary_email']==mail时添加。

尝试一下，我重构了您的代码。

In [25]: for mail in match_list:
    ...:     for d in data:
    ...:         if d['entity']['primary_email']==mail:
    ...:             first_name.append(d['entity']['first_name'])
    ...:             emails.append(d['entity']['primary_email'])

输出

In [26]: emails
Out[26]: ['jane@fakemail.com']

In [27]: first_name
Out[27]: ['Jane']

从嵌套字典中提取匹配值

3 个答案: